Answer:
Π = iMRT ½
Explanation:
111 g
= 0.033 mol
0.033 mol CaCl2
0.09632 kg solvent
= 0.0344 m
13.7 g x 1 mol C3H7OH
60.10 g
0.5 L
(0.0821 L.atm/K.mol) (300.15K
Answer:
1 mole =22.4 L of gas at STP. So now 1 mole of H2 gas weighs equal to 2 grams.
Explanation:
Answer:
ion-dipole
Explanation:
Let us remember that the potassium cation is an ion, a positive ion to be precise.
There is a dipole existing in the hydrogen cyanide molecule. The positive end of the dipole is on hydrogen while the negative end of the dipole is on the cyanide moiety.
The only possible interaction between the potassium cation and the hydrogen cyanide is an ion dipole interaction. The cation interacts with the cyanide moiety having a partial negative charge in the molecule.
Answer:
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Explanation:
Step 1: Data given
Moles ethane produced = 13.78 moles
Step 2: The balanced equation
C2H2 + 2H2 → C2H6
Step 3: Calculate moles of hydrogen
For 1 mol acetylene (C2H2) we need 2 moles hydrogen (H2) to produce 1 mol of ethane (C2H6)
For 13.78 moles ethane produced we need 2*13.78 = 27.56 moles hydrogen (H2)
We need 27.56 moles hydrogen to produce 13.78 mol of ethane. (option 3)
Different colors of sedimentary rock are determined by the environment where they are located. For example, red rocks form where oxygen is present. Darker sediments form when the environment is oxygen poor.
So, basically, the weather and surroundings of the rock, so B.
