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ira [324]
3 years ago
11

2.In a titration, 25.00 cm3 of a solution of hydrochloric acid reacted with 18.40 cm3 of sodium hydroxide solution of concentrat

ion 0.15 mol/dm3.
The equation which represents the reaction is:
HCl + NaOH -----> NaCl + H2O
Calculate the concentration of hydrochloric acid in mol/dm3
Chemistry
1 answer:
telo118 [61]3 years ago
4 0

Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

             HCl   +  NaOH  →  NaCl + H₂O

Volume of acid  = 25cm³  = 0.025dm³

Volume of base  = 18.4cm³ = 0.0184dm³

Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

 To solve this problem, let us first find the number of moles of the base;

 Number of moles  = concentration x volume

 Number of moles  = 0.15mol/dm³ x 0.0184dm³  = 0.00276mol

From the balanced reaction equation;

          1 mole of NaOH will combine with 1 mole of HCl

Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

  Concentration of acid  = \frac{number of moles }{volume}   = \frac{ 0.00276}{0.025}   = 0.11mol/dm³

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What is the transfer of electrons in Al + Cl = AlCl3
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Answer:

3 e⁻ transfer has occurred.

Explanation

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A combination of both the reactions( Half-reactions) leads to a redox reaction.

Let us look at initial configurations of Al and Cl

[Al]= 1s² 2s² 2p⁶ 3s² 3p¹

[Cl]= 1s² 2s² 2p⁶ 3s² 3p⁵

Hence, Al can lose 3 electrons to achieve octet config.

and, Cl can gain 1e to achieve nearest noble gas config. [Ar]

This reaction can be rewritten, by clearly mentioning the oxidation states of all the entities involved.

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Here, Aluminum is undergoing an oxidation(i.e loss of electrons) from: 0→(+3)

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Answer:

Mean

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The mean of a series of measurements is calculated when a<em>ll the measurements are added up and then divided by the number of measurements taken</em>, as follows:

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As<u> there are 4 measurements</u>, the mean is:

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2 years ago
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Answer:

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Explanation:

The reaction to produce water between H₂ and O₂ is this:

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We don't have the amount of hydrogen, so we have to think that is in excess.

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Ratio is 1:2

For 0.5 mole of oxygen, I will make the double of moles of water.

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3 years ago
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