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Tanya [424]
3 years ago
10

Given y=(2x+3)2, choose the standard form of the given quadratic equation

Mathematics
2 answers:
Naddika [18.5K]3 years ago
6 0

Rewrite using the formula for the standard form

The answer is y-4x^2 + 12x + 9

Kisachek [45]3 years ago
4 0

Answer: y-4x^{2} +12x+9=0

Step-by-step explanation:  the standard form of a quadratic equation can be writen in the form: ax2 + bx + c = 0. To transform the given equation into the standard form, we need to solve it:

y=(2x+3)^{2}

y=4x^{2} +2*2x*3+3^{2}

y=4x^{2} +12x+9

no we reorganize it, and equal it to zero:

y-4x^{2} +12x+9=0

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6 0
2 years ago
If a polynomial function f(x) has roots 3 and square root of 7, what must also be a root of f(x)
Neko [114]

Answer:

x = - \sqrt{7}

Step-by-step explanation:

Radical roots occur in pairs, that is

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3 0
3 years ago
Read 2 more answers
Jan plans to spend $100 on a pair of jeans and shirts. She buys 2 shirts for $24 each. What is the most she can spend on the jea
Volgvan

Answer:

52

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3 years ago
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The question that is asked
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The answer is A because 157 is to wide because it’s smaller then 23.
7 0
3 years ago
Write an equation in point-slope form of the line that passes through the given point and with the given slope, m
bearhunter [10]
Equation format for a slope, m and a point (x1, y1)

y - y1  = m(x - x1)      (Try and memorize this formula)

8) for (3,-4),  m = 6.    x1 = 3,  y1 = -4, Substituting
y - y1  = m(x - x1)
y - (-4)  = 6(x - 3)
y + 4  = 6x - 18
y = 6x - 18 - 4
y = 6x - 22

10) for (-2,-7),  m = 4/5.    x1 = -2,  y1 = -7, Substituting
y - y1  = m(x - x1)
y - (-7)  = (4/5)*(x - (-2))
y + 7  = (4/5) *(x +2)                      4/5 = 0.8
y + 7  = 0.8x  + 1.6
y = 0.8x + 1.6-7
y = 0.8x - 6.4
y = (4/5)x - (64/10)
y = (4/5)x - (32/5)

So same approach to solve others. Cheers.
8 0
3 years ago
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