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Mekhanik [1.2K]
4 years ago
9

Whicj of the following ions would represent the ion of an element from group 2A

Chemistry
1 answer:
lina2011 [118]4 years ago
5 0
A2 hope that helps :) :) :)
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Which of these statements is true ?
uysha [10]

Answer:

I believe it's C

Explanation:

KHDUDCM

King Henry Died Unexpectedly Drinking Chocolate Milk

cL is C and L is U so you go back two decimal points on 6000. That is 60 so you have 60 L and 6 L and 60L > 6L

7 0
3 years ago
What does a velocity measurement include that a speed measurement does not?
Mars2501 [29]
Velocity is speed and Direction. It does not include direction
4 0
3 years ago
2. You have a 2.50 mole gas sample in a 500.0 mL flask at 25.0 °C.
SIZIF [17.4K]

Considering the ideal gas law, the pressure of the gas sample is 122.18 atm.

<h3>What is an ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Definition of ideal gas law</h3>

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

<h3>Pressure of the gas sample</h3>

In this case, you know:

  • P= ?
  • V= 500 mL= 0.5 L
  • n= 2.50 moles
  • R= 0.082 \frac{atm L}{mol K}
  • T= 25 °C= 298 K

Replacing in the ideal gas law:

P×0.5 L = 2.50 moles ×0.082 \frac{atm L}{mol K} ×298 K

Solving:

P= (2.50 moles ×0.082 \frac{atm L}{mol K} ×298 K)÷ 0.5 L

<u><em>P= 122.18 atm</em></u>

Finally, the pressure of the gas sample is 122.18 atm.

Learn more about the ideal gas law:

brainly.com/question/4147359

#SPJ1

7 0
2 years ago
A public school district furnishes pencils to its elementary students. The pencils the secretary orders from the district wareho
IRINA_888 [86]

Minimum number of boxes order is 52.4 boxes.

<u>Given that;</u>

Average use of pencil per student = 9.3 pencil per year

Number of student in school = 812 students

<u>Find:</u>

Minimum number of boxes order

<u />

<u>Computation:</u>

Total number of pencil used in year = 812 × 9.3

Total number of pencil used in year = 7,551.6 pencils

12 <u>dozen</u> = 1 <u>gross</u>

So,

Number of pencils in 1 box = 12 × 12

Number of pencils in 1 box = 144 pencils

Minimum number of boxes order = 7551.6 / 144

Minimum number of boxes order = 52.4 boxes

Learn more:

brainly.com/question/3838477?referrer=searchResults

5 0
2 years ago
A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density
VMariaS [17]

A 10.0cm3 volume of alcohol has a mass of 7.05g. 0.705 \frac{g}{c m^{3}} is the density

Answer:  0.705 \frac{g}{c m^{3}}

<u>Explanation:</u>

The ratio between the mass of a substance and its unit volume is referred as density.

\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}} is the Answer

<u>Note:</u>

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}

Alcohol’s volume can be written as, 10.0 c m^{3} = 10 \times 10^{-2} m^{3}

Alcohol’s mass can denote as, 7.05 g = 7.05 \times 10^{-3} \mathrm{kg}

Then, \text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}

4 0
4 years ago
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