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Fittoniya [83]
2 years ago
6

How many hydrogen atoms are attached to each carbon participating in a double bond?

Chemistry
1 answer:
vfiekz [6]2 years ago
4 0

In a double bond there are two hydrogen atoms attached to each carbon

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Water (2230 g ) is heated until it just begins to boil. If the water absorbs 5.73×105 J of heat in the process, what was the ini
shutvik [7]

Answer: 38.5^0C

Explanation:

To calculate the initial temperature of the water:

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = 5.73\times 10^5J

c = specific heat of water = 4.18J/g^oC

m = mass of water = 2230 g

T_{final} = final temperature of water = 100^0C

T_{initial} = initial temperature of metal = ?

Now put all the given values in the above formula, we get:

5.73\times 10^5J=2230g\times 4.18J/g^oC\times (100-T_i)^0C

(100-T_i)=61.5

T_i=100-61.5)=38.5^0C

Thus, the initial temperature of the water is 38.5^0C

5 0
3 years ago
Is crumpling a piece of paper chemical changes
kenny6666 [7]
No, because you are not changing the chemical make-up of the paper
8 0
3 years ago
Read 2 more answers
Uranium, an important component of both nuclear weapons and nuclearreactors, has two major isotopes, U-238, which has a half-lif
elixir [45]

Answer:

Hello your question is poorly written below is the well written question

Uranium, an important component of both nuclear weapons and nuclear reactors, has two major isotopes, U-238, which has a half-life of  approximately 4.5 billion years, and U-235, which has a half-life of approximately 700 million years. Both were present in equal amounts at the time of the creation of the Earth, 4.5  billion years ago. How many years after the creation of the Earth had the amount of radiation from uranium decayed to half the amount present at the time of the creation of the Earth

Answer : 140 billion years

Explanation:

Given that :

U-238   h1/2 = 4.5 billion years

U-235   h1/2 = 700 million years

At the beginning both Isotopes where present in equal amount

Determine the T years before the amount of Uranium decays to Half

T =   ?    N'2 = N1 / 2

we know that N = No ( 1/2 )^h   where h = time / half-life time

attached below is the detailed solution of the given problem

6 0
2 years ago
What is the hybridization of the carbon atoms in 1,3-butadiene, h2c=ch-ch=ch2?
Natalija [7]
The main formula is as follow  is explained in the attached file  (please look at the examples)

the 1,3- butadiene is h2c=ch-ch=ch2, so we have 

sp²             sp²     sp²               sp²
h2c    =     ch   -     ch         =      ch2

<span>the hybridization of the carbon atoms  is </span>sp²  : trigonal planar

4 0
3 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be
Stels [109]

Explanation:

1) Initial mass of the Cesium-137=N_o= 180 mg

Mass of Cesium after time t = N

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

Half life of the cesium-137 = t_{1/2}=30 years[p/tex]where,&#10;[tex]N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

N=180mg\times e^{-\frac{0.693}{30 years}\times t}

Mass that remains after t years.

N=180 mg\times e^{0.0231 year^{-1}\times t}

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

N_o=180 mg

t_{1/2}= 30 yeras

N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

N_o=180 mg

t_{1/2}= 30 yeras

N = 1 mg

t = ?

1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}

\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0
3 years ago
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