Question

A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density

Answer 1

A 10.0cm3 volume of alcohol has a mass of 7.05g. $0.705 \frac{g}{c m^{3}}$ is the density

Answer:  $0.705 \frac{g}{c m^{3}}$

Explanation:

The ratio between the mass of a substance and its unit volume is referred as density.

$\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}}$ is the Answer

Note:

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

$\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}$

Alcohol’s volume can be written as, $10.0 c m^{3} = 10 \times 10^{-2} m^{3}$

Alcohol’s mass can denote as, $7.05 g = 7.05 \times 10^{-3} \mathrm{kg}$

Then, $\text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}$