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Vlada [557]
4 years ago
5

Find the rms speed of the molecules of a sample of n2 (diatomic nitrogen) gas at a temperature of 32.5°c.

Chemistry
1 answer:
Korvikt [17]4 years ago
5 0
The rms speed of a gas can be calculated using the following rule:
Vrms = sqrt[(3RT) / M] where
R is the gas constant = 8.314 <span>J K^−1 mol^−1
T is the temperature = 32.5 + 273 = 305.5 degree kelvin
M is the molar mass = 2*14 = 28 grams = 0.028 kg

Substitute with the givens in the equation to get the rms speed as follows:
Vrms = sqrt [(3*8.314*305.5) / 0.028]
Vrms = 521.665 m/sec</span>
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<h3>Answer:</h3>

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<h3>Explanation:</h3>
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  • Methane is a hydrocarbon in the homologous series known as alkanes.
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CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)

<u>We are given;</u>

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We are required to determine the mass of H₂O produced

<h3>Step 1: Moles of H₂O produced</h3>
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Therefore, Moles of methane = Moles of H₂O × 2

Hence, Moles of H₂O = 7.0 moles

<h3>Step 2: Mass of H₂O produced </h3>

We know that; mass = Moles × Molar mass

Molar mass of water = 18.02 g/mol

Therefore;

Mass of water = 7.0 moles × 18.02 g/mol

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Thus, the mass of water produced is 126.14 g

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