All categories

3 years ago

If a reaction is reversible what are the relative amounts of reactant and product

2 answers:

3 0

<span>If a reaction is reversible, then it will attain the phase of Equilibrium and at that phase, the Amount of Reactants and Products would be: Equal

Hope this helps!</span>

JulsSmile [24]3 years ago

3 0

Answer:

Some product and some reactant

Explanation:

You might be interested in

Which particle is most likely present in the nucleus of the atom

k0ka [10]

Oh protons and neutrons

8 0

2 years ago

Read 2 more answers

Slicing an average loaf of bread gives 13 medium thickness slices. Each slice of bread is to be coated with 0.0500 oz of mayonna

AlexFokin [52]

Answer:

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

Explanation:

Number of slices of ham = 231

Given that each sandwich has 1 slice of ham.

Then 231 slices of ham will be in :

$1\times 231 =231 sandwiches$

A single sandwich is made up of 2 bread slices , Then bread slices in 231 sandwiches will be :

$231\times 2=462$

Each bread slice is applied with 0.0500 ounce of mayonnaise.

Then 462 bread slices will have :

$462\times 0.0500 ounces=18.48 Oz$

1 bread loaf = 13 bread slices

Then breads loves in 462 bread slices :

$\frac{462}{13}=35.54\approx 36$

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

8 0

3 years ago

Which is the correct chemical symbol for this atom of helium?

Tomtit [17]

H........................................

6 0

2 years ago

This week in lab you will use the spectrovis plus spectrophotometer to measure the light that is absorbed by dopachrome, a dark

NARA [144]

A solution that appears dark orange in color is not absorbing all orange wavelengths of light.

6 0

3 years ago

A reaction that is second-order in one reactant has a rate constant of 1 × 10–2 L/mol · s. If the initial concentration of the r

Harlamova29_29 [7]

Answer : It take time for the concentration to become 0.180 mol/L will be, 277.8 s

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $1\times 10^{-2}mol/L.s$

t = time taken = ?

[A] = concentration of substance after time 't' = 0.180 mol/L

$[A]_o$ = Initial concentration = 0.360 mol/L

Putting values in above equation, we get:

$1\times 10^{-2}=\frac{1}{t}\left (\frac{1}{0.180}-\frac{1}{0.360}\right)$

$t=277.8s$

Hence, it take time for the concentration to become 0.180 mol/L will be, 277.8 s

7 0

3 years ago