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LuckyWell [14K]

3 years ago

5

Rubber bands provided the thrust to get your rocket going. Why did the rocket keep moving after it left the launch pad and the r

ubber bands were no longer pushing it?

1 answer:

BARSIC [14]3 years ago

3 0

Answer:

rocket engines

Explanation:

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The water level in a tank is 20 m above the ground. A hose is connected to the bottom of the tank, and the nozzle at the end of

weeeeeb [17]

Answer:

$P_{pump}= 68600Pa$

Explanation:

We understand that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

In this way,

$P_{tank} + P_{pump} = P_{nozzle}$

For the pressure we also know that it is given by

$P=\rho gh$

$\rho gh_1 + P_{pump} = \rho gh_2$

So,

$P_{pump} = \rho g(h2 - h1)$

$P_{pump}= 1000*9.8(27-20)$

$P_{pump}= 68600Pa$

7 0

3 years ago

Question Set 22.1 Using the count method, find the number of occurrences of the character 's' in the string 'mississippi'.2.2 In

Gnom [1K]

Answer:

# Program is written in python

# 22.1 Using the count method, find the number of occurrences of the character 's' in the string 'mississippi'.

# initializing string

Stringtocheck = "mississippi"

# using count() to get count of s

counter = Stringtocheck.count('s')

# printing result

print ("Count of s is : " + str(counter))

# 2.2 In the string 'mississippi', replace all occurrences of the substring 'iss' with 'ox

# Here, we'll make use of replace() method

# Prints the string by replacing iss by ox

print(Stringtocheck.replace("iss", "ox"))

#2.3 Find the index of the first occurrence of 'p' in 'mississippi'

# declare substring

substring = 'p'

# Find index

index = Stringtocheck.find(substring)

# Print index

print(index)

# End of program

8 0

3 years ago

Steel balls 12 mm in diameter are annealed by heating to 1150 K and then slowly cooling to 400 K in an air environment for which

luda_lava [24]

Answer:

It will take the steel 425.925sec to cool from 1150k to 400k

Explanation:

Detailed explanation and calculation is shown in the image

6 0

3 years ago

A car accelerates from rest with an acceleration of 5 m/s^2. The acceleration decreases linearly with time to zero in 15 s, afte

Tpy6a [65]

Answer: At time 18.33 seconds it will have moved 500 meters.

Explanation:

Since the acceleration of the car is a linear function of time it can be written as a function of time as

$a(t)=5(1-\frac{t}{15})$

$a=\frac{d^{2}x}{dt^{2}}\\\\\therefore \frac{d^{2}x}{dt^{2}}=5(1-\frac{t}{15})$

Integrating both sides we get

$\int \frac{d^{2}x}{dt^{2}}dt=\int 5(1-\frac{t}{15})dt\\\\\frac{dx}{dt}=v=5t-\frac{5t^{2}}{30}+c$

Now since car starts from rest thus at time t = 0 ; v=0 thus c=0

again integrating with respect to time we get

$\int \frac{dx}{dt}dt=\int (5t-\frac{5t^{2}}{30})dt\\\\x(t)=\frac{5t^{2}}{2}-\frac{5t^{3}}{90}+D$

Now let us assume that car starts from origin thus D=0

thus in the first 15 seconds it covers a distance of

$x(15)=2.5\times 15^{2}-\farc{15^{3}}{18}=375m$

Thus the remaining 125 meters will be covered with a constant speed of

$v(15)=5\times 15-\frac{15^{2}}{6}=37.5m/s$

in time equalling $t_{2}=\frac{125}{37.5}=3.33seconds$

Thus the total time it requires equals 15+3.33 seconds

t=18.33 seconds

3 0

3 years ago

If you are sampling a 50Hz signal, what is the minimum sampling rate necessary to prevent aliasing?Why?

horsena [70]

Answer:

100Hz

Explanation:

The minimum sampling rate to prevent aliasing is at least double your sample frequency.

50*2 = 100Hz

This is called the Nyquist Sampling Rate if you wanna learn more about it.

6 0

4 years ago