Answer:
The kinetic energy of the weight is 344.5 J
Explanation:
Given that:
Force = F = 65 newton
distance = d = 5.3 meters
We have to find change in kinetic energy ΔK.E
Now we know that, initially kinetic energy was 0 So the formula we use will be:
Work done = Change in kinetic energy
Mathematically,
W = ΔK.E
As we know W = F . d and ΔK.E = K.E(final) - K.E(initial)
So by putting values:
F . d = K.E(final) - K.E(initial)
F . d = K.E(final)
As K.E(initial) is 0 so by putting values of F and d
(65)* (5.3) = K.E(final)
344.5 J = K.E(final)
So the change in K.E will also be 344.5 J
i hope it will help you!
3-SAT ≤p TSP
If P ¹ NP, then no NP-complete problem can be solved in polynomial time.
both the statements are true.
<u>Explanation:</u>
- 3-SAT ≤p TSP due to any complete problem of NP to other problem by exits of reductions.
- If P ¹ NP, then 3-SAT ≤p 2-SAT are the polynomial time algorithm are not for 3-SAT. In P, 2-SAT is found, 3- SAT polynomial time algorithm implies the exit of reductions. 3 SAT does not have polynomial time algorithm when P≠NP.
- If P ¹ NP, then no NP-complete problem can be solved in polynomial time. because for the NP complete problem individually gets the polynomial time algorithm for the others. It may be in P for all the problems, the implication of latter is P≠NP.
Hoiu-10,4000 mm.
<h3>
Is positive pressure good for PC?</h3>
- A balanced configuration is the most efficient way to cool your pc although it should tend towards a slight positive pressure if you can help it.
- Tip: As much as it might seem important, the concept of heat rising doesn't have too much of an effect.
To learn more about it, refer
to https://brainly.in/question/413163
#SPJ4
Answer:
Technician A is wrong
Technician B is right
Explanation:
voltage drop of 0.8 volts on the starter ground circuit is not within specifications. Voltage drop should be within the range of 0.2 V to 0.6 V but not more than that.
A spun bearing can seize itself around the crankshaft journal causing it not to move. As the car ignition system is turned on, the stater may draw high current in order to counter this seizure.
