Answer:
The answer to your question is m = 4.7 kg
Explanation:
Data
Ice Water
mass = ? mass = 711 g
T₁ = -13°C T₁ = 87°C
T₂ = 10°C T₂ = 10°C
Ch = 2090 J/kg°K Cw = 4180 J/kg°K
Process
1.- Convert temperature to kelvin
T₁ = 273 + (-13) = 260°K
T₁ water = 87 + 273 = 360 °K
T₂ = 10 + 273 = 283°K
2.- Write the equation of interchange of heat
- Heat lost = Heat absorbed
- mwCw(T₂ - T₁) = miCi(T₂ - T₁)
-Substitution
- 0.711(4180)(10 - 87) = m(2090)(10 - (-13))
- Simplification
228842.46 = 48070m
m = 228842.46/48070
-Result
m = 4.7 kg
Answer:
Dana filtered the sample and larger granules of the sample were left behind.
Explanation:
If a substance is pure, it will have a uniform composition throughout. It will not separate into particles of various sizes.
One of the characteristics of pure substances is that they are homogeneous. A mixture is definitely made up of particles of various sizes.
Since the particles was filtered and larger granules were left behind, the sample has been separated by a physical method (filtration). Only a mixture can be separated by physical methods. It is not a pure substance.
Answer:
3
Explanation:
The mass has 4 sig digits.
The volume has 3 sig digits
The density is = 11.50/9.03 = 1.2735
To 3 sig digits (determined by 9.03) the answer would be 1.27 gram/mL
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