Rate of Sulfur dioxide : 2730.44 mL/s
<h3>Further explanation </h3>
Graham's law: <em>the rate of effusion of a gas is inversely proportional to the square root of its molar masses or </em>
the effusion rates of two gases = the square root of the inverse of their molar masses:
![\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7Br_1%7D%7Br_2%7D%3D%5Csqrt%7B%5Cdfrac%7BM_2%7D%7BM_1%7D%20%7D)
or
![\rm M_1\times r_1^2=M_2\times r_2^2](https://tex.z-dn.net/?f=%5Crm%20M_1%5Ctimes%20r_1%5E2%3DM_2%5Ctimes%20r_2%5E2)
MW of N₂ = 28 g/mol
MW SO₂ = 64 g/mol
![\tt 28\times 79^2=64\times r_2^2\\\\r_2^2=\dfrac{28\times 79^2}{64}=2730.44~mL/s](https://tex.z-dn.net/?f=%5Ctt%2028%5Ctimes%2079%5E2%3D64%5Ctimes%20r_2%5E2%5C%5C%5C%5Cr_2%5E2%3D%5Cdfrac%7B28%5Ctimes%2079%5E2%7D%7B64%7D%3D2730.44~mL%2Fs)
Answer:
Einstein realized that the energy in electrons was caused by the frequency of light and not the intensity of light. This made him realize that he needed to explain the photoelectric effect.
Explanation:
Einstein realized that the photoelectric effect was a system that should be studied and explained in more depth, when he saw how the energy of electrons behaved in the presence of light. He saw that this energy depends entirely on the frequency of light and not on the intensity of light. From this observation, he realized that the photoelectric effect was essential for the production of an electric energy system, through light energy, such as solar energy.
It is important to note that the photoelectric effect refers to the ejection of electrons on a light surface that comes into contact with a light source.
Answer:
right now we are using energy by online learning on our laptops , air conditioning, and transportation
Explanation:
Answer:
oxygen atoms gain electrons and hydrogen atoms lose electron
Explanation:
Hydrogen oxygen fuel cell involves redox reactions.
It is an electrochemical cell, which is used for many applications like rocket propellant.
The actual reaction is
![H_{2}+\frac{1}{2}O_{2}--->H_{2}O](https://tex.z-dn.net/?f=H_%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7DO_%7B2%7D---%3EH_%7B2%7DO)
Here hydrogen undergoes oxidation as it loses electrons
Oxygen undergoes reduction as it gains electrons.
The redox reactions are
At anode:
[loss of electrons by hydrogen]
At cathode:
[gain of electrons by oxygen]