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lesantik [10]
3 years ago
14

The element, boron, is represented by which of the following chemical symbols? Be Br B Ba

Chemistry
2 answers:
Solnce55 [7]3 years ago
8 0
Boron is represented by just "B"

So, option C is your answer.

Hope this helps!
LenaWriter [7]3 years ago
7 0
Your answer would be B. Hope this helps!
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Name the reaction type & mechanism of the following reactions:
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Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

4 0
2 years ago
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Predict and Balance the following reaction:
Umnica [9.8K]

A. The balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

<h3>What is a balanced chemical equation? </h3>

A balanced equation contains the same number of each type of atoms on both the left and right sides of the reaction arrow.

<h3>Reaction of Sodium metal and Water</h3>

Sodium metal reacts rapidly with water to form a colourless solution of sodium hydroxide (NaOH) and hydrogen gas (H2).

The balanced chemical reaction is written below;

2Na  +  2H₂O  →  2NaOH    +   H₂

Thus, the balanced chemical reaction of Sodium metal and Water is 2Na  +  2H₂O  →  2NaOH    +   H₂.

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8 0
1 year ago
Do all substances absorb heat the same way?
miv72 [106K]

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5 0
3 years ago
A compound is 80.0% carbon and 20.0% hydrogen by mass. assume you have a 100.-g sample of this compound. the molar mass of the c
ch4aika [34]
Basis of the calculation: 100g
 
For Carbon: 
 Mass of carbon = (100 g)(0.80) = 80 g
  Number of moles of carbon = (80 g)(1 mole / 12g) = 20/3

For Hydrogen:
  Mass of hydrogen = (100 g)(0.20) = 20 g
     Number of moles of hydrogen = (20 g)(1 mole / 1 g) = 20

Translating the answer to the formula of the substance,
     C20/3H20

Dividing the answer,
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The molar mass of the empirical formula is:
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Since, the molar mass given for the molecular formula is 30.069 g/mol, the molecular equation is,
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ANSWER: C2H6

 
4 0
3 years ago
Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at
valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100  - x  

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,  

121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042

120.9038x+122.9042\left(100-x\right)=12176.01

Solving for x, we get that:

x = 57.2 %

<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>

<u>percentage abundance of 123 Sb is = 100 - 57.2 %  = 42.8 %</u>

6 0
3 years ago
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