Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
Answer:
a) ΔV = 0.1875 V
, b) v = 9.73 m / s
Explanation:
For this exercise we can use Necton's second law, as the speed is constant the forces on the driver are equal
= 0
= F_{B}
q E = q v B
E = v B
The electrical force induced in the conductor is
ΔV = E l
ΔV = v B l
Let's calculate
ΔV = 2.5 0.75 0.10
ΔV = 0.1875 V
b) If ΔV = 0.73 what speed should it have
v = DV / B l
v = 0.73 / 0.75 0.1
v = 9.73 m / s
Answer:
27.78 s
Explanation:
Assume ideal gas, since pressure and temperature of the air inside the balloon is the same as air entering the balloon, then the volume (and its rate) stays the same.
The cross-sectional area of the hole where air enters
Hence the volume rate:
The total volume of the spherical balloon is
Hence the time it takes to fill this much at a constant rate of 3π/4 is
Answer:
Pressure = 20 MPa
Explanation:
Given:
Force acting on the shoe is,
Area of shoe on which the force acts is,
Now, first we convert the area into its standard unit of m².
We have the conversion factor as:
1 cm² =
Therefore, the area of shoe in square meters is given as:
Now, pressure on the shoe is given as:
Plug in 100 N for 'F', for 'A' and solve for 'P'. This gives,
Now, we know that,
Therefore, the pressure acting on the shoe is 20 MPa.