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Masja [62]
3 years ago
8

The zone along the southern margins of the Sahara is called the

Physics
1 answer:
Jobisdone [24]3 years ago
7 0
We have to choose the correct name for the zone along the southern margins of the Sahara. Laterite is a soil in hot and wet tropical areas. Savanna is the tropical grassland. It has tropical savanna climate. Veldt is name for the areas in the South Africa. Finally, the Sahel is the zone along the south margins of the Sahara. It has a semi-arid climate. The Arabic word "sahel" means "coast". Answer: C. Sahel. <span> </span>
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According to the principle of faunal succession, what must be true of the fossils on a layer below? Now
Firdavs [7]
It means that they were set earlier therefor they are older.
7 0
2 years ago
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PLease help me WIll give brainliest
melisa1 [442]

Answer:

6

Explanation:

3 0
2 years ago
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s
Vlad1618 [11]

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

F_D = mg

where

F_D is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

g=9.8 m/s^2 is the acceleration of gravity

Substituting into the formula, we find:

F_D = (80)(9.8)=784 N

Learn more about forces here:

brainly.com/question/8459017

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4 0
3 years ago
A musician on a unicycle is riding at a steady 6.2 m/s while playing their well tuned oboe at an A above middle C (440 Hz). They
Verizon [17]

Answer:

The frequency of the beat is  f_t =  8Hz    

Explanation:

From the question we are told that

   The speed of the ride v = 6,2 m/s

   The frequency of the oboe is  f = 440Hz

    The temperature outside is  T = 27^oC

Generally the speed of sound generated in air is mathematically evaluated as

             v_s = 331  + 0.61 T

Substituting value

           v_s = 331 + 0.61 *27

           v_s = 347.47 \ m/s

The frequency of sound(generated by the musician on he park) getting to the musicians on the unicycle is mathematically evaluated as

                 f_a =  \frac{v_s }{v_s - v} f

substituting values

                f_a =  \frac{347.47 }{347.47  - 6.2} * 440                

               f_a =  448Hz

Since the musician on the park is not moving the frequency of sound (from the musicians riding the unicycle )getting to him is  = 440Hz

    The beat frequency these musician here is mathematically evaluated as

                  f_t = f_a - f  

So               f_t = 448 - 440  

                  f_t =  8Hz    

3 0
3 years ago
Which of the following is an example of refraction?
Sladkaya [172]
I believe it will be C.
7 0
2 years ago
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