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3 years ago

1.) What statement best explains the type of population growth seen in Belize according to the 2010 age structure diagram?

Physics

1 answer:

Art [367]3 years ago

7 0

Answer:

1. Belize has a high birth rate and a low death rate.

2. Belize will have a rapidly growing population over the next twenty years.

Explanation:

Belize has a high birth rate and a low death rate. Belize is in the phase II of the demographic transition model. Their population is growing exponentially. This is due to lowering death rates while the birth rates are still high.

Belize will have a rapidly growing population over the next twenty years. When the age structure diagram has a wider base than the middle or top age groups, this indicates a population that is rapidly growing. Belize is early in the transition model and still has high birth rates. Countries like Belize typically have lower opportunities for education for women of reproductive age, can have high infant mortality, and can have high emigration rates.

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A striped billiard ball moves toward the right with speed 3 m/s. A solid billiard ball with the same mass moves toward the left

Helen [10]

Answer:

Final speed of striped ball is 3 m/s in left direction .

Explanation:

Given :

Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .

Let , us assume right hand side direction to be positive and left hand side direction to be negative .

Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .

It is also given that the collision is elastic .

Therefore , kinetic energy is conserved .

$\dfrac{m(3)^2}{2}+\dfrac{m(3)^2}{2}=\dfrac{mu^2}{2}+\dfrac{mv^2}{2}\\\\u^2+v^2=18$ ...... ( 1 )

Also , by conserving linear momentum .

We get :

$3m-3m=mu+mv\\u=-v$ ...... ( 2 )

Putting value of u from equation 2 to equation 1 .

We get :

$2v^2=18\\v=3\ m/s$

And , u = -3 m/s .

Therefore , final speed of striped ball is 3 m/s in left direction .

Hence , this is the required solution .

4 0

3 years ago

What units is the Metric System of Measurement based on?

Alex787 [66]

Answer:

metre for length and the kilogram for Mass

3 0

3 years ago

You have two golf balls that differ only in their surfaces. one has dimples, while the other is smooth. if you were to drop the

il63 [147K]

Answer: the golf ball with smooth surface would hit the ground first.

Jusitification:

An analysis of forces show two vertical forces acting on the golf balls.

1) one force is the weight (mg) which is vertical downward

2) the other force is the drag force exerted by the air on the golf balls, and it is vertical upward.

3) the drag force opposes the weight, so the acceleration downward is determined by the difference of the weiight and the drag force, until the balls reach the terminal speed (when the drag force equals the weight).

4) the drag force depends on the shape and area of the object falling. Being the surface of one ball smooth implies that the drag force will be less than the one on the other ball.

5) less drag force implies that the terminal velocity of the smooth ball will he higher, ant then it will hit the ground first.

3 0

3 years ago

What is the weight of a 7.0 kilogram bowling ball on the surface of the moon

Artist 52 [7]

The acceleration on surface of moon =1.67m/s^2

Weight =mass ×acceleration
=7×1.67
=11.69N

8 0

3 years ago

A runner of mass 53.0 kg runs around the edge of a horizontal turntable mounted on a vertical, frictionless axis through its cen

const2013 [10]

Answer:

0.336 rad/s

Explanation:

$\omega_1$ = Angular speed of the turntable = -0.2 rad/s

R = Radius of turntable = 2.9 m

I = Moment of inertia of turntable = $76\ kgm^2$

M = Mass of turn table = 53 kg

$v_1$ = Magnitude of the runner's velocity relative to the earth = 3.6 m/s

As the momentum in the system is conserved we have

$Mv_1R+I\omega_1=(I + MR^2)\omega_2\\\Rightarrow \omega_2=\dfrac{Mv_1R+I\omega_1}{I + MR^2}\\\Rightarrow \omega_2=\dfrac{53\times 3.6-76\times 0.2}{76+53\times 2.9^2}\\\Rightarrow \omega_2=0.336\ rad/s$

The angular velocity of the system if the runner comes to rest relative to the turntable which is the required answer is 0.336 rad/s

4 0

3 years ago