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3 years ago

10. What does a profile of a river from its headwaters to its mouth typically show?

Engineering

1 answer:

irina1246 [14]3 years ago

3 0

Answer:

c. an abrupt increase followed by a gradual decrease

Explanation:

At the headwater, the flow gradient starts high but then slowly decreases as the river moves downstream to its mouth.

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Nutka1998 [239]

Answer:

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3 years ago

Water is contained in a piston-cylinder assembly undergoes four processes separately, all started from an initial state where th

Andrews [41]

Answer:

see pictures

Explanation:

In the pictures you can see the different processes.

3 0

3 years ago

Draw perpendicular lines based on the info in the image.

Over [174]

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5 0

3 years ago

An aluminum block weighing 28 kg initially at 140°C is brought into contact with a block of iron weighing 36 kg at 60°C in an in

Anika [276]

Answer:

Equilibrium Temperature is 382.71 K

Total entropy is 0.228 kJ/K

Solution:

As per the question:

Mass of the Aluminium block, M = 28 kg

Initial temperature of aluminium, $T_{a} = 140^{\circ}C$ = 273 + 140 = 413 K

Mass of Iron block, m = 36 kg

Temperature for iron block, $T_{i} = 60^{\circ}C$ = 273 + 60 = 333 K

At 400 k

Specific heat of Aluminium, $C_{p} = 0.949\ kJ/kgK$

At room temperature

Specific heat of iron, $C_{p} = 0.45\ kJ/kgK$

Now,

To calculate the final equilibrium temperature:

Amount of heat loss by Aluminium = Amount of heat gain by Iron

$MC_{p}\Delta T = mC_{p}\Delta T$

$28\times 0.949(140 - T_{e}) = 36\times 0.45(T_{e} - 60)$

Thus

$T_{e} = 109.71^{\circ}C$ = 273 + 109.71 = 382.71 K

where

$T_{e}$ = Equilibrium temperature

Now,

To calculate the changer in entropy:

$\Delta s = \Delta s_{a} + \Delta s_{i}$

Now,

For Aluminium:

$\Delta s_{a} = MC_{p}ln\frac{T_{e}}{T_{i}}$

$\Delta s_{a} = 28\times 0.949\times ln\frac{382.71}{413} = - 2.025\ kJ/K$

For Iron:

$\Delta s_{i} = mC_{i}ln\frac{T_{e}}{T_{i}}$

$\Delta s_{a} = 36\times 0.45\times ln\frac{382.71}{333} = 2.253\ kJ/K$

Thus

$\Delta s =-2.025 + 2.253 = 0.228\ kJ/K$

6 0

3 years ago

A circuit contains a resistor, an inductor, and a capacitor. When an AC voltage is applied across the circuit, the impedance of

katen-ka-za [31]

Answer:

The impedance of the circuit depends on the angular frequency of the voltage source.

Explanation:

In a electric circuit, the magnitude of the impedance, is given by the following expression:

$Z = \sqrt{R^{2} + (Xl-Xc)^{2} (1)$

where R = Resistance

Xl = Inductive reactance = ω*L

Xc = Capacitive Reactance = 1/ωC

and ω = angular frequency of the voltage source.

So, it can be seen that the impedance depends on the value of the constants R,L and C, and on the angular frequency ω.

3 0

3 years ago