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2 years ago

What is the value of the expression-2(3x-2)+x+9 when x= -3

Mathematics

1 answer:

nikitadnepr [17]2 years ago

4 0

We know x=-3

Replace x with -3

-2(3[-3]-2)+(-3)+9

simplify

-2(-9-2)-3+9

-2(-11)-3+9

22-3+9

do math

22-12

Your Answer Is 10

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What is an equation of the line that passes through the point (3,-1) and (8, 9)?

Evgesh-ka [11]

Answer:

4) y = 2x - 7

Step-by-step explanation:

First we have to find the slope by using the following formula....

let (3, - 1) be $(x_{1}, y_{1} )$ , let (8, 9) be $(x_{2} ,y_{2} )$ , and m be the slope, then....

$m = \frac{y_{2} -y_{1} }{x_{2} - x_{1} } = \frac{9 + 1}{8 - 3} = \frac{10}{5} = 2$

Now that we know the slope we can find the equation of the function by using point-slope for of the function which look like this.....

$y -y_{1} = m(x - x_{1} )\\y + 1 = 2(x - 3)\\y + 1 = 2x - 6\\y = 2x - 7$

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3 years ago

In 3.62 what does the 3 stand for??

victus00 [196]

Answer:

3 stands for the main amount.

Step-by-step explanation:

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3 years ago

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Which statement is most likely to be true? the ages of the mackerels are the most dispersed from the team’s mean. the ages of th

MakcuM [25]

The ages of the Stars are the most dispersed from the team’s mean

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2 years ago

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3 years ago

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Find the dot product of the position vectors whose terminal points are (14, 9) and (3, 6).

erma4kov [3.2K]

Answer:

Step-by-step explanation:

The formula for the dot product of vectors is

u·v = |u||v|cosθ

where |u| and |v| are the magnitudes (lengths) of the vectors. The formula for that is the same as Pythagorean's Theorem.

$|u|=\sqrt{14^2+9^2}$ which is $\sqrt{277}$

$|v|=\sqrt{3^2+6^2}$ which is $\sqrt{45}$

I am assuming by looking at the above that you can determine where the numbers under the square root signs came from. It's pretty apparent.

We also need the angle, which of course has its own formula.

$cos\theta=\frac{uv}{|u||v|}$ where uv has ITS own formula:

uv = (14 * 3) + (9 * 6) which is taking the numbers in the i positions in the first set of parenthesis and adding their product to the product of the numbers in the j positions.

uv = 96.

To get the denominator, multiply the lengths of the vectors together. Then take the inverse cosine of the whole mess:

$cos^{-1}\theta=\frac{96}{111.64676}$ which returns an angle measure of 30.7. Plugging that all into the dot product formula:

$u*v=\sqrt{277}*\sqrt{45}cos(30.7)$ gives you a dot product of 96

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2 years ago