Answer:A)3074m,3074.37m/s
B)12905.4m,19100.54m/s
Explanation:the formula for electric field =V/d
Where V=velocity of the particle,d=distance covered from the electric field source
A)E=V/d
1.48=4.55×10^5/d
d=4.55×10^5/1.48=3074m
Distance of B from centre of the field=3074+0.370=3074.370m
B)d=V/E=1.91×10^4/1.48
d=12905.4m
At point B
Distance=12905.4+0.370=12905.770
V=Ed=12905.770×1.48=19100.54m/s
Answer:
about 19.6° and 73.2°
Explanation:
The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...
y = -4.9(x/s·sec(α))² +x·tan(α)
where s is the launch speed in meters per second.
We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):
-13.6111·tan(α)² +50·tan(α) -16.0511 = 0
This has solutions ...
tan(α) = 0.355408 or 3.31806
The corresponding angles are ...
α = 19.5656° or 73.2282°
The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.
_____
I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.
Answer:
0.4344A
Explanation:
From Ampere's law, it can be shown that the magnetic field B inside a long solenoid is
Where
B= Magnetic field strenght at distance d
I= current
Permeability of free space ()
N= Number of loops
Our values are defined as follow,
T
As a current required to become 104 times the Earth's magnetic field is required, we use B '
<em>Therefore is needed 0.4344A in the solenoid to produce a magnetic field inside the solenoid, near its center, that is 104 times the Earth's magnetic field.</em>
Normal force, weight, Kinetic friction, and air resistance are a few I think of the top of my head.
I hope this helps
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