Velocity differs from speed in that velocity indicates a particle's <span>direction of motion.
Therefore, your correct answer is: D</span><span>irection
Good luck with your studies, I hope this helps~!</span>
Answer:
At 3.86K
Explanation:
The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:
gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2
Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .
We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =
√0.7/ 0.0469 = 3.86K.
Answer:
The moment of inertia of the wheel is 0.593 kg-m².
Explanation:
Given that,
Force = 82.0 N
Radius r = 0.150 m
Angular speed = 12.8 rev/s
Time = 3.88 s
We need to calculate the torque
Using formula of torque



Now, The angular acceleration


We need to calculate the moment of inertia
Using relation between torque and moment of inertia




Hence, The moment of inertia of the wheel is 0.593 kg-m².
Doppler Effect is required to solve the problem. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. The general formula of observed frequency, due to Doppler's effect is as follows,

= Frequency observed by observer
v = Velocity of Sound
= Velocity of observer
= Velocity of source
= Frequency of source
PART A) Replacing our values we have that,



PART B) Here the same procedure is performed but this time repeated in the opposite direction.



The type of star is the north star