Answer:
Mass of the ring is 2.5 kg.
Given:
Moment of inertia of a ring = 0.4 kg.
Radius = 40 cm = 0.4 m
To find:
Mass of the ring = ?
Formula used:
I = m
Where I = moment of inertia
r = radius of the ring
m = mass of the ring
Solution:
Moment of inertia of a ring is given by,
I = m
Where I = moment of inertia
r = radius of the ring
m = mass of the ring
0.4 = m ×0.4×0.4
m = 0.4/(0.4×0.4)
m = 1/0.4
m = 2.5 kg
Mass of the ring is 2.5 kg.
Answer:
3.6 kHz
Explanation:
The pipes behave like a closed pipe . The end open is the end of the air canal outside the ear and the closed end is the eardrum.
The first harmonic will be as seen in the figure attached.
The length of the first harmonic will be λ/4.
λ/4=2.4 cm
λ=2.4 * 4=9.6 cm 0.096 m
Speed of Sound- 344 m/s(in air)
velocity(v) * Time Period(T) = Wavelength (λ)
Also, Time Period(T)= \frac{\textrm{1}}{\textrm{Frequency(f)}}
\frac{\textrm{Velocity}}{\textrm{Wavelength}}=\frac{\textrm{1}}{\textrm{Time Period}} =Frequency
Plugging in the values into the equation,
Frequency = Hz
= 3583.3 Hz≈3600 Hz= 3.6 kHz
Frequency= 3.6 kHz
