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JulijaS [17]
3 years ago
12

The diagram shows waves of sound travelling through the air. By which factor is the sound intensity decreased at 3 meters?

Physics
2 answers:
SIZIF [17.4K]3 years ago
8 0
The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
I(r)= \frac{1}{r^2}
where I is the intensity and r is the distance from the source.

We can assume for instance that the initial distance from the source is r=1 m, so that we put 
I= \frac{1}{r^2}= \frac{1}{(1)^2}=1
The intensity at r=3 m will be
I= \frac{1}{r^2}= \frac{1}{(3)^2}= \frac{1}{9}
Therefore, the sound intensity has decreased by a factor 1/9.
RSB [31]3 years ago
3 0

its a  on edge just finished my exam

heres the diagram

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Answer:

a) speed when Jack sees the pot : 12.92 meters per second

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Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

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v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

Solving for v0 it would be

v1 - a*t = v0

replacing

58 m/s -  9.8 m/s^2 *4.6 s = v0 = 12.92 m/s

For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

The formula is

y0 + v0*t + 1/2 g *t^2 = yt

replacing

0m + 12.92m/s* 4.6 s + 1/2 * 9.8 m/s^2 * (4.6 s)^2 = 163.115 m

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melomori [17]

Answer:

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