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mariarad [96]
4 years ago
12

for: rate=k[A]^x determine the value of x if the rate doubles when [A] is doubled; and if the rate quadruples when [A] is double

d.,
Chemistry
2 answers:
Rom4ik [11]4 years ago
5 0
<span>1. The value of x if the rate doubles when [A] is doubled is that </span><span>x = 1 

</span><span>2. Then if the rate quadruples when [A] is doubled is that x= 2
Since x=1 when the rate doubles, so if it quadruples, it will be times 2.
So the solution to this is 1 times 2= 2
x=2</span>
rewona [7]4 years ago
3 0

Answer:

  • If the rate doubles when [A] is doubled,  x = 1
  • If the rate quadruples when  [A] is doubled, x=2

Explanation:

We have the equation for the rate:

r=k[A]^{x}  equation 1

  • For the first case, we  can rewrite the equation 1, as follows:

2r=k[2A]^{x}=2^{x}k[A]^{x}  equation 2

<em>Replacing  equation 1 in 2, we get:</em>

2r=2^{x}r

Then x must be equal to 1, in order to satisfy equality

  • For the second case, we  can rewrite the equation 1, as follows:

4r=k[2A]^{x}=2^{x}k[A]^{x}  equation 3

<em>Replacing equation 1 in 3, we get:</em>

4r=2^{x}r

Then x must be equal to 2, in order to satisfy equality

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