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scoray [572]
4 years ago
5

What are some similarities between ice wedging and plant root growth in rock

Chemistry
1 answer:
Lostsunrise [7]4 years ago
5 0
The both Crack what they are growing through
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If a pure compound is distilled, the head temperature will be____compared to the pot temperature. If however, an impurity is pre
shutvik [7]

Answer:

If a pure compound is distilled, the temperature of the head will be compared to the temperature of the pot. However, if there is an impurity present that strongly interacts with the molecules of the liquid, then the temperature must be increased to increase the vapor pressure of the liquid, eventually to atmospheric pressure, allowing the liquid to boil. Therefore, at the boiling point, the temperature of the pot will be higher than the temperature of the head.

Explanation:

when temperatures increase, pressures also do so, thus reaching boiling points where liquid states become gaseous.

4 0
3 years ago
If someone is whispering, but you can't hear them, how do you fix that problem?
Maurinko [17]
I'D SAY D IS THE ANSWER
5 0
3 years ago
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Predict products or C3H8 + O2 via combustion
EastWind [94]
When propane   is  burned  in  air  in  a process  known  as  combustion  it  produce   carbon  (IV) oxide  and  water
 the  word  equation  is  as follows,
  propane + oxygen--->carbon (IV)  oxide + water
chemical  equation  is  as follows
  2C3H8  +7O2--->  3CO2  + 8 H2O
hence  2 moles  of propane  reacted with 7  moles  of  oxygen  to  give 3  moles of  CO2  and  8  moles  of  H2o
4 0
3 years ago
What is the molar mass of methanol (CH3OH)?
HACTEHA [7]
Molar mass of methanol=12 + 1×3 + 16 + 1=32g
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8 0
3 years ago
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A hamburger containing 335.4 kcal of energy was combusted in a bomb calorimeter with an unknown heat capacity. The temperature o
Zielflug [23.3K]

Answer:

Cv_{calorimeter}=18.4kcal/K

Explanation:

Hello!

In this case, since the combustion of the hamburger released 335.4 kcal of energy and that energy is received by the calorimeter, we can write:

Q_{hamburguer}=-Q_{calorimeter}

And the heat of the calorimeter is written in terms of the temperature change and the calorimeter constant:

Q_{hamburguer}=-Cv_{calorimeter}\Delta T

Thus, given the released heat by the hamburger due to its combustion and the temperature change, Cv for the calorimeter turns out:

Cv_{calorimeter}=\frac{-Q_{hamburguer}}{\Delta T} =\frac{-(-335.4kcal)}{18.2K}\\\\Cv_{calorimeter}=18.4kcal/K

Best regards!

4 0
3 years ago
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