When light of frequency equal to 2.40 × 1015 s−1 shines on the surface of silver metal, the kinetic energy of ejected electrons
1 answer:
You might be interested in
The equation (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.
The horizontal momentum is given by:
Where:
- m₁: is the mass of the lab cart = 15 kg
- m₂: is the <em>mass </em>of the object dropped = 2 kg
: is the initial velocity of the<em> lab cart </em>
: is the <em>initial velocit</em>y of the <em>object </em>= 0 (it is dropped)
: is the final velocity of the<em> lab cart </em>
: is the <em>final velocity</em> of the <em>object </em>
Then, the horizontal momentum is:
When the object is dropped into the lab cart, the final velocity of the lab cart and the object <u>will be the same</u>, so:
Therefore, the equation represents the horizontal momentum (option 3).
Learn more about linear momentum here:
I hope it helps you!
Maybe this will help you out:
Momentum is calculate by the formula:
Where:
P = momentum
m = mass
v = velocity
The SI unit:
So the unit of momentum would be:
Impulse is defined as the change in momentum or how much force changes momentum. It can be calculate with the formula:
I = FΔt
where:
I = impulse
F = Force
Δt = change in time
The SI unit:
F = Newtons (N) or
t = Seconds (s)
So the unit of impulse would be derived this way:
I = FΔt
I = x
or
You can then cancel out one s each from the numerator and denominator and you'll be left with:
So then:
Momentum: Impulse