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zzz [600]
3 years ago
15

When light of frequency equal to 2.40 × 1015 s−1 shines on the surface of silver metal, the kinetic energy of ejected electrons

is found to be 5.9 × 10−19 J. What is the work function of silver? Enter your answer in scientific notation.
Physics
1 answer:
sesenic [268]3 years ago
3 0

Answer: 9.98 *10^-19 J

Explanation: In order to explain this probelm we have to consider the balance enegy for photoelectric effect.

h*f-W=Ek where h is the Planck constant and W the work function and Ek the kinetic energy. f is the frequency of light.

W=h*f-Ek=6.62*10^-34*2.4*10^15-5.9*10^-19=9.98*10^-19J

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v' = 3.76 m/s.

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