Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 N, and it doesn't budge. The magnitude of the friction force on the crate in Newton is 400N
This is due to Friction force, which is defined as the resisting force that acts on a body when it is at rest (Static friction) or when it is in motion (Kinetic friction).
When a force is applied on a stationary body, the force of static friction starts to act on the body which prevents any relative motion between the object and surface. The magnitude of friction increases up to μsN, where μs is the coefficient of static friction. As the crate didn't budge, it means the amount of force applied was less than μsN. Hence the force applied was canceled by an equal and opposite amount of frictional force which was equal to 400N.
Learn more about frictional force here
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The answer is; NASA's New Horizons spacecraft
It was launched in 2006 from Cape Canaveral and engineered by the Johns Hopkins University. The spacecraft has flown past Pluto, collected data and is now exploring the Kuiper belt object. The mission involved mapping of the planet's surface and check for atmosphere.
Answer:
hi
Explanation:
The answer is Responding Variables Hope this helps :D
Answer:
A
B
Explanation:
From the question we are told that
The wavelength is 
The angle of first bright fringe is 
The order of the fringe considered is n =1
Generally the condition for constructive interference is
=> 
=> 
Converting to cm
Generally the number of grating pre centimeter is mathematically represented as
=> 
=>
Considering question B
From the question we are told that
The first wavelength is 
The second wavelength is 
The order of the fringe is 
The grating is 
Generally the slit width is mathematically represented as
=> 
=> 
Generally the condition for constructive interference for the first ray is mathematically represented as
=> ![\theta_1 = sin^{-1} [\frac{ 2 * \lambda }{d}]](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%5Clambda%20%7D%7Bd%7D%5D)
=> ![\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20650%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> 
Generally the condition for constructive interference for the second ray is mathematically represented as
=> ![\theta_2 = sin^{-1} [\frac{ 2 * \lambda_1 }{d}]](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%5Clambda_1%20%7D%7Bd%7D%5D)
=> ![\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}]](https://tex.z-dn.net/?f=%5Ctheta_2%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B%202%20%2A%20%20%20420%20%2A10%5E%7B-9%7D%20%7D%7B%202%2A10%5E%7B-6%7D%7D%5D)
=> 
Generally the angular separation is mathematically represented as
=> 
=>
Answer:
the answers the correct one is cη
Explanation:
In this simple pendulum experiment the student observes a significant change in time between each period. This occurs since an approximation used is that the sine of the angle is small, so
sin θ = θ
with this approach the equation will be surveyed
d² θ / dt² = - g / L sin θ
It is reduced to
d² θ / dt² = - g / L θ
in which the time for each oscillation is constant, for this approximation the angle must be less than 10º so that the difference between the sine and the angles is less than 1%
The angle is related to the height of the pendulum
sin θ = h / L
h = L sin θ.
Therefore the student must be careful that the height is small.
When reviewing the answers the correct one is cη
