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sattari [20]
2 years ago
11

What is the kinetic energy of 0.01kg bullet traveling at a velocity of 700m/s ?

Physics
1 answer:
Nata [24]2 years ago
5 0

Answer:

kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie.

Explanation:

In the given question, we are told that what is the kinetic energy of mass M equals 0.1 kg bullet traveling at a velocity Velocity is given and 700 m/s. So we know that kinetic energy mm-hmm k equals one half m v squared. So this will be mass is given 0.1 and velocity is 700 so 700 square this is one half 0.1 in two 49 double zero, double zero. This is one-half into 49 double zero. So kinetic energy is 2, 4, 50 thirties, 2.45 into 10, raise to three Julie. This is kinetic energy. Thank you.

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Analyze why a body undergoing uniform motion eventually comes to rest even in the
djverab [1.8K]

Answer:

It happens due to force of friction

Explanation:

If a body is performing a uniform motion and no external unbalanced force appears to apply on it, then  the body will come to rest after certain time. The reason behind this is the force of friction that is applied in opposite direction of the motion. So, when there is no apparent unbalanced force it means that the only force acting on the body is the force of friction. This force of friction tends to stop the motion after some period of time, because it is acting in the direction opposite to that of motion.

Hence, the reason behind a body undergoing uniform motion eventually stops is <u>Force of Friction.</u>

8 0
3 years ago
PLEASE HELP ASAP! This is an emergency!
dsp73
1. A
2. B 
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3 years ago
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What are the horizontal and vertical velocities of a stunt bike that leaves a ramp at 100 km/hr and at an angle of 35 degrees?
Alex787 [66]

Horizontal velocity: 81.9 km/h

Vertical velocity: 57.4 km/h

Explanation:

We can solve this problem by resolving the velocity vector into its component along the horizontal and vertical direction.

The horizontal velocity of the stunt bike is given by:

v_x = v cos \theta

where

v = 100 km/h is the magnitude of the velocity

\theta=35^{\circ} is the angle of projection

Substituting, we find

v_x = (100)(cos 35^{\circ})=81.9 km/h

The vertical velocity instead is given by

v_y = v sin \theta

where

v=100 km/h

\theta=35^{\circ}

Substituting,

v_y = (100)(sin 35^{\circ})=57.4 km/h

Learn more about vector components:

brainly.com/question/2678571

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4 0
3 years ago
Which of the following is not an example of projectile motion?
Ilia_Sergeevich [38]
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4 0
4 years ago
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A spinning wheel on a fireworks display is initially rotating in a counterclockwise direction. The wheel has an angular accelera
nalin [4]

Answer:

5.74s

Explanation:

We can first solve for the initial angular velocity using the following formula

\omega^2 - \omega_0^2 = 2\alpha\theta

Where \omega = -22.4rad/s is the final angular velocity, \alpha = -22.4 rad/s^2is the angular acceleration and \theta = 0 is the angular displacement

22.4^2 - \omega_0^2 = 2*(-7.8)*0

\omega_0^2 = 22.4^2

\omega_0 = 22.4rad/s

So for the wheel to get from 22.4 to -22.4 with angular acceleration of -7.8 then the time it takes must be

t = \frac{\Delta \omega}{\alpha} = \frac{-22.4 - 22.4}{-7.8} = 5.74s

8 0
3 years ago
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