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3 years ago

Assuming a constant force, if the mass of an object increases, the acceleration of the object will

Physics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

Assuming a constant force, if the mass of object increases, the acceleration will decrease and if mass of a object decreases, the acceleration will increase. Also if the force applied to object increases the acceleration will also increase whereas if the force applied decreases, the acceleration will also decrease.

Explanation:

We know that according to newton's second law of motion,

F = ma, where F is force applied, m is mass of an object and a is measure of body accelerated with the applies force.

a = F/m

Assuming force is constant, we get

a α 1/m, that is acceleration is inversely proportional to mass. Hence if mass of an object decreases the acceleration of object will increases and vice versa.

Also from equation, F = ma, we infer that F α a . That is the force applied is directly proportional to amount the body is accelerated. . Hence if force applied increases then the acceleration will also increase and vice versa

Anettt [7]3 years ago

4 0

For Edgeunity its decrease, increase, increase, and decrease

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A soccer player takes a corner kick, lofting a stationary ball 30.0° above the horizon at 18.0 m/s. If the soccer ball has a mas

Radda [10]

Answer:

change in momentum, $\Delta p=7.65 \,kg.m.s^{-1}$

$\Delta p_x= 6.6251 \,kg.m.s^{-1}$

$\Delta p_y= 3.825 \,kg.m.s^{-1}$

Average Force, $F=144.3396\,N$

$F_x=125.0018\,N$

$F_y=72.1698\,N$

Explanation:

Given:

angle of kicking from the horizon, $\theta= 30^{\circ}$

velocity of the ball after being kicked, $v=18 m.s^{-1}$

mass of the ball, $m=0.425\, kg$

time of application of force, $t=5.3\times 10^{-2}\,s$

We know, since body is starting from the rest

$\Delta p=m.v$ .....................(1)

$\Delta p=0.425\times 18$

$\Delta p=7.65 \,kg.m.s^{-1}$

Now the components:

$\Delta p_x= 7.65\times cos 30^{\circ}$

$\Delta p_x= 6.6251 \,kg.m.s^{-1}$

similarly

$\Delta p_y= 7.65\times sin 30^{\circ}$

$\Delta p_y= 3.825 \,kg.m.s^{-1}$

also, impulse

$I=F\times t$ .........................(2)

where F is the force applied for t time.

Then from eq. (1) & (2)

$F\times t=m.v$

$F\times 5.3\times 10^{-2}= 7.65$

$F=144.3396\,N$

Now, the components

$F_x=144.3396\times cos 30^{\circ}$

$F_x=125.0018\,N$

$F_y=144.3396\times sin 30^{\circ}$

$F_y=72.1698\,N$

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3 years ago

The diagram below shows the different phase transitions that occur in matter.

Margaret [11]

Answer:A

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Liquid are made up of molecules that moves more freely than solids. When heat is added to liquid,the molecules gain more energy and begins to move faster. This causes them to turn to gases.

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Ilia_Sergeevich [38]

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Serggg [28]

Answer:

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Explanation:

First, find the mass in kg:

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Fg(moon) = 59.69 kg * 1.60 m/s^2

Fg(moon) = 95.51 N

Hope this helps!! :)

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3 years ago