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Serggg [28]
3 years ago
6

Assuming a constant force, if the mass of an object increases, the acceleration of the object will

Physics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

Assuming a constant force, if the mass of object increases, the acceleration will decrease and if mass of a object decreases, the acceleration will increase. Also if the force applied to object increases the acceleration will also increase whereas if the force applied decreases, the acceleration will also decrease.

Explanation:

We know that according to newton's second law of motion,

F = ma, where F is force applied, m is mass of an object and a is measure of body accelerated with the applies force.

a = F/m

Assuming force is constant, we get

a α 1/m, that is acceleration is inversely proportional to mass. Hence if mass of an object decreases the acceleration of object will increases and vice versa.

Also from equation, F = ma, we infer that F α a . That is the force applied is directly proportional to amount the body is accelerated. . Hence if force applied increases then the acceleration will also increase and vice versa

Anettt [7]3 years ago
4 0

For Edgeunity  its decrease, increase, increase, and decrease

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Answer:

n = 1.76

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4 years ago
Noah is loading the ark and the last animal on board is a stubborn 1500-kg elephant who refuses to budge. Noah and his family pu
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The coefficient of sliding friction is 0.514

Explanation:

We start by writing the equations of motion of the elephant along the two directions, parallel and perpendicular, to the incline.

Along the parallel direction we have:

F- mg sin \theta - \mu_k R = ma (1)

where :

F = 10,000 N is the force applied by Noah

mg sin \theta is the component of the weight parallel to the incline, where:

m is the mass

g = 9.8 m/s^2 the acceleration of gravity

\theta=10^{\circ}  is the angle of incline

\mu_k R is the force of friction, where:

\mu_k is the coefficient of friction

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and a is the acceleration

Perpendicular direction:

R-mg cos \theta =0 (2)

where mg cos \theta is the component of the weight perpendicular to the incline

From (2) we find

R=mg cos \theta

And substituting into (1)

F-mg sin \theta - \mu_k mg cos \theta = ma

We know that the elephant moves at constant speed, so the acceleration is zero:

a = 0

So the equation becomes

F-mg sin \theta - \mu_k mg cos \theta=0

And we can re-arrange it to find the coefficient of friction:

F-mg sin \theta - \mu_k mg cos \theta=0\\\mu_k = \frac{F-m g sin \theta}{mg cos \theta}=\frac{10000-(1500)(9.8)(sin 10)}{(1500)(9.8)(cos 10)}=0.514

Learn more about friction and inclined planes:

brainly.com/question/5884009

#LearnwithBrainly

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