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Serggg [28]
3 years ago
6

Assuming a constant force, if the mass of an object increases, the acceleration of the object will

Physics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

Assuming a constant force, if the mass of object increases, the acceleration will decrease and if mass of a object decreases, the acceleration will increase. Also if the force applied to object increases the acceleration will also increase whereas if the force applied decreases, the acceleration will also decrease.

Explanation:

We know that according to newton's second law of motion,

F = ma, where F is force applied, m is mass of an object and a is measure of body accelerated with the applies force.

a = F/m

Assuming force is constant, we get

a α 1/m, that is acceleration is inversely proportional to mass. Hence if mass of an object decreases the acceleration of object will increases and vice versa.

Also from equation, F = ma, we infer that F α a . That is the force applied is directly proportional to amount the body is accelerated. . Hence if force applied increases then the acceleration will also increase and vice versa

Anettt [7]3 years ago
4 0

For Edgeunity  its decrease, increase, increase, and decrease

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A heavy boy and a lightweight girl are balanced on a mass-less seesaw. If they both move forward so that they are one-half their
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Answer:

b) Nothing will happen,  the sea saw will still be balanced.

Explanation:

b) Nothing will happen,  the sea saw will still be balanced.

Reason:-

When two kids are balanced, the sum of torques on the seesaw will be zero.

if each kid, reduces their distances by half, then the torque of each kid will be half and the sum of torque of each on the seesaw will be zero.

Therefore the seesaw is balanced

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1. Hydrogen

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State the law of conservation of energy​
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In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. ... For instance, chemical energy is converted to kinetic energy when a stick of dynamite explodes.

7 0
2 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

    gm = 1/6 ge

    gm = 1/6  9.8 m/s² = 1.63 m/s²

We calculate the range

    R = Vo² sin 2θ  / g

    R = 25² sin (2 30) / 1.63

    R= 332 m

We will calculate the time of flight,

   Y = Voy t – ½ g t2  

   Voy = Vo sin θ

When the ball reaches the end point has the same initial  height Y=0

0 = Vo sin  t – ½  g t2

0 = 25 sin (30)  t – ½ 1.63 t2

0= 12.5 t –  0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

 t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

5 0
3 years ago
A 1000kg car is rolling slowly across a level surface at 1 m/s heading twoards a group o fsmall innocent children. The doors are
Degger [83]

Answer:

The force required to push to stop the car is 288.67 N

Explanation:

Given that

Mass of the car, m = 1000 kg

Initial speed of the car, u = 1 m/s

The car and push on the hood at an angle of 30° below horizontal, \theta=30^{\circ}

Distance, d = 2 m

Let F is the force must you push to stop the car.

According work energy theorem theorem, the work done is equal to the change in kinetic energy as :

W=\dfrac{1}{2}m(v^2-u^2)F\times d=\dfrac{1}{2}m(v^2-u^2)

v = 0

Fd\ cos\theta=\dfrac{1}{2}m(u^2)      F=\dfrac{\dfrac{1}{2}m(u^2)}{d\ cos\theta}F=\dfrac{\dfrac{1}{2}\times 1000\times (1)^2}{2\ cos(30)}F = -288.67 N

The force required to push to stop the car is 288.67 N

3 0
2 years ago
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