Answer:
and the forces acting on the particle as a function of time.
Explanation:
The principle of linear impulse and momentum is obtained by integrating the equation of motion with respect to time. hope this helps you :)
Answer:
The magnitude of the force on the truck is equal to the magnitude of the force on the car
Explanation:
The law of action and reaction states that when two bodies interact the forces are of equal magnitude, but of the opposite direction, each acts in one of the bodies. Let's analyze each sentence
The magnitude of the force on the truck is smaller than the magnitude of the force on the car. False. the forces are of equal magnitude
The truck does not exert a force on the car during the collision. False. The forces are always in pairs
The magnitude of the force on the truck is equal to the magnitude of the force on the car. True forces are equal magnitude
The magnitude of the force on the truck is larger than the magnitude of the force on the car. False. They are of equal magnitude
The car does not exert a force on the truck during the collision. False forces are in pairs
Answer:
Wavelength,
Explanation:
Given that,
Speed of the sound in the rat tissues, v = 1500 m/s
Let is the wavelength of an ultrasonic wave. The speed of a wave is given by the relation as follows:
Let us assume that the frequency of ultrasonic wave is 2.3 MHz.
So, the wavelength of an ultrasonic wave is . Hence, this is the required solution.
Answer:
physicist use it at mechanics,moves,senmatic,denamics and more
R = 0.407Ω.
The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.
To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.
We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:
R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]
R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²
R = 0.407Ω