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Step2247 [10]
3 years ago
9

A golf club consists of a shaft connected to a club head. The golf club can be modeled as a uniform rod of length ℓ and mass m1

extending radially from the surface of a sphere of radius R and mass m2. Find the location of the club's center of mass, measured from the center of the club's head. (Use the following as necessary: m1, m2, ℓ, and R.)
Physics
1 answer:
slega [8]3 years ago
5 0

Answer:

 m₁ (R +ℓ/2) / /( m₁ + m₂ )

Explanation:

We shall consider centre of the club's head  as origin .

The centre of mass of the rod attached with sphere will be away from the centre of sphere by a distance

= R + ℓ /2 and its mass is m₁

mass of sphere is m₂ and distance of its centre of mass from origin is zero

So required CM = m₁ x₁ + m₂ x₂ / ( m₁ + m₂ )

= m₁ (R + ℓ /2) + m₂ x 0 /( m₁ + m₂ )

=  m₁ (R +ℓ/2) / /( m₁ + m₂ )

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How many meters in 2.50 miles? (Use these two conversions: 1000 m = 1 km and 1.00 km = .621 mi )
Artyom0805 [142]

2.50 miles is equal to 4026 m.

<u>Explanation:</u>

As it is known that 1000 m =1 km and 1 km = 0.621 miles. So first we have to convert miles to km and then to metre as follows.

As 1 km = 0.621 miles, then

             \text { 1 miles }=\frac{1}{0.621} \mathrm{km}

So, 2.50 miles will be equal to

            2.50 \text { miles }=\frac{2.50}{0.621} \mathrm{km}=4.026 \mathrm{km}

Then, in order to get the answer in meters, we have to convert this km to meter by the conversion of 1000 m =1 km.  So,

           1 \mathrm{km}=1000 \mathrm{m}

Thereby,

          4.026 \mathrm{km}=4026 \mathrm{m}

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2 years ago
When magnesium fluoride reacts with iodine, the products are fluorine and magnesium iodide. What would the equation be?
likoan [24]

Answer:

Explanation:

Every chemical reaction can be represented by simple chemical equations that shows how compounds are combining to give some products.

Such reactions are usually made up of:

     Reactants on the left hand side

     Products on the right hand side

            Reactants  →  Products

In this given problem;

            Reactants are :   Magnesium fluoride  = MgF₂

                                             Iodine in form of Iodide   = I₂

           Product : Magnesium iodide  = MgI₂

             

               MgF₂   +     I₂    →       MgI₂   +   F₂

   

                             

   

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3 years ago
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I took the test and it was correct. I hope this helps!

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3 years ago
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6)An electric field of 6 N/C points in the positive X direction. What is the electric flux through a surface that is 4 m2, if it
Salsk061 [2.6K]

Answer:

Flux is 21 Nm^2/C.

Explanation:

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Electric filed vector, E = 6 i N/C

Area, A = 4 square meter

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\overrightarrow{A} = 4 (cos30 \widehat{i} + sin 30 \widehat{j})\\\\\overrightarrow{A} = 3.5 \widehat{i} + 2 \widehat{j}\\

The flux is given by

\phi= \overrightarrow{E}.\overrightarrow{A}\\\\\phi = 6 \widehat{i} .  \left (3.5 \widehat{i} + 2 \widehat{j}  \right )\\\\\phi = 21 Nm^2/C

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