All except burning gasoline
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure, T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa
∴ on rearranging above eq., we get V2 =
∴ V2 = 4 m3
It doesn't transfer through Thermalizing
In this question, you are given the wine/alcohol concentration (12%) and the volume of the alcohol(0.75l). You are asked the alcohol content in milli liters, so don't forget to change the unit. Then the equation would be:
Alcohol content= alcohol concentration * bottle volume
Alcohol content = 12%* 0.75l * 1000ml/l= 90ml
Answer:
answer is 77.45grams you use stoichimetric formula by comparing CaCl2 and Agcl