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Alla [95]
3 years ago
8

What is the scientific notation of 38,802,000

Chemistry
1 answer:
SpyIntel [72]3 years ago
6 0
That would be 3.8802 * 10^7
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Calculate the pH of a 0.2 M * 4 solution for which Kb = 1.8*10^-5 at 26 c . The equation for the reaction
lara31 [8.8K]

<u>Answer:</u> The pH of the solution is 11.24

<u>Explanation:</u>

We are given:

Molarity of ammonia = 0.2 M

K_b=1.8\times 10^{-5}

The given chemical equation follows:

                NH_3+H_2O\rightleftharpoons NH_4^++OH^-

I:                0.2

C:               -x                      +x        +x

E:             0.2-x                     x          x

The expression for equilibrium constant follows:

K_b=\frac{[NH_4^+][OH^-]}{[NH_3]}

Putting values in above expression, we get:

1.8\times 10^{-5}=\frac{x^2}{0.2-x}\\\\1.8\times 10^{-5}(0.2-x)=x^2\\\\x^2+(1.8\times 10^{-5}x)-(0.36\times 10^{-5})=0\\\\x=1.88\times 10^{-3}, 1.9\times 10^{-3}

Neglecting the negative value of x as concentration cannot be negative.

So, [OH^-]=x=1.88\times 10^{-3}M

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution.

pOH=-\log [OH^-]

Putting values in above equation, we get:

pOH=-\log (1.88\times 10^{-3})\\\\pOH=2.76

We know:

pH+pOH=14\\\\pH=14-2.76\\\\pH=11.24

Hence, the pH of the solution is 11.24

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