Answer:

Explanation:

Total distance = 2 m + 30 m = 32 m
Total time = 2 s + 40 s = 42 s

Answer:
addition of aqueous hydrochloric acid
Explanation:
The solubility of copper (ll) hydroxide in water is negligible. This implies that the substance is only slightly soluble in water.
However, the addition of aqueous hydrochloric acid leads to the following reaction;
Cu(OH)2 + 2HCl ---------> CuCl2 + 2H2O
Copper II chloride is soluble in water hence the crystals dissolve when stirred. and the molar solubility increases.
Answer:

Explanation:
Hello,
In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:

We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:

Best regards.
Answer:
The answer is Bob
Explanation:
The science exist to kinds of measurements base units and derive units of measurement.
Base units are the ones that measure: length, mass, time, electric current, temperature, luminous intensity and amount of substance.
Derivative units of measurement are obtain when we combine the base units.
Know from your question
Bob measures length is a base unit
Jill measures density is a derivative unit, is the combination of mass and volumen
Kim measures mass is a base unit
Steve measures brightness is a base unit.
Answer:
THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.
Explanation:
Mass of the unknown substance = 0.50 g
Freezing point of the solution = 3.9 °C
Freezing point of pure benzene = 5.5 °C
Freezing point dissociation constant Kf = 5.12°C/m
First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.
Change in temperature = 5.5 -3.9 = 1.6 °C
Next is to calculate the number of moles or molarity of the compound that dissolved.
Using the formula:
Δt = i Kf m
Assume i = 1
So,
1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene
x = 1.6 * 0.008 / 5.12
x = 0.0128 / 5.12
x = 0.0025 moles.
Next is to calculate the molar mass using the formula, molarity = mass / molar mass
Molar mass = mass / molarity
Molar mass = 0.50 g /0.0025
Molar mass = 200 g/mol
Hence, the molar mass of the unknown compound is 200 g/mol