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Natasha2012 [34]
3 years ago
6

What part of an Atom undergoes change during radioactive decay

Chemistry
1 answer:
Aloiza [94]3 years ago
7 0
It is clear that the core is subject to change
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MnS+HCl H 2 S+MnCl 2 Which set of coefficients would balance the equation?
Gnom [1K]

Answer:

1,2,1,1

Explanation:

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3 years ago
Classify each as either a solid a liquid or a gas at room temperature
LenKa [72]

Answer:

air gas

diamond solid

copper solid

candle wax solid or melted would be liquid

Explanation:

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2 years ago
Which member of the following pairs has the larger London dispersion forces?
Virty [35]

Answer:

H₂S; CO₂; SiH₄

Explanation:

London dispersion forces are larger in molecules that are large and have more atoms or electrons.

A. H₂O or H₂S

H₂S. S is below O in the Periodic Table, so it is the larger atom. Its electrons are more polarizable.

B. CO₂ or CO

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C. CH₄ or SiH₄

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4 0
3 years ago
The liquids hexane and water are placed in a test tube. The test tube is stoppered, shaken, and placed in a test tube rack. The
Diano4ka-milaya [45]

The liquids hexane and water are placed in a test tube. The test tube is stoppered, shaken, and placed in a test tube rack. The liquids separate into two distinct layers because hexane and water have different molecular polarities. The answer is number 2.

5 0
2 years ago
Read 2 more answers
The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

Best regards.

8 0
3 years ago
Read 2 more answers
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