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kvasek [131]
3 years ago
8

1 Flower color D. What color are the parents?

Chemistry
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

what is the baby flowers color?

Explanation:

if the baby flower is purple the parents were purple

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4. Did the complete process of photosynthesis take place in the way you modeled it in this activity? Explain your answer
weqwewe [10]
Hello!

This question requires a model -- you'll have to do that yourself. However, I can explain the steps for the process:

• Chlorophyll absorbs the sun's energy.

• The energy is used to split water molecules into hydrogen and oxygen.

• The oxygen is released from the leaves into the atmosphere.

• The hydrogen and carbon dioxide glucose (food) for plants.

If you have any more questions related to this assignment, please let me know!
7 0
4 years ago
5. The density of a substance is 3.4 X 10^3 g/mL. Mixing it with another substance increases the density by 1.5 X 10^1 times. Wh
JulijaS [17]

Answer:

the total density of the mixture = 3.415 x 10^3 g/mL

Explanation:

given:

density of a substance is 3.4 x 10^3 g/mL

Mixing it with another substance increases the density by 1.5 x 10^1 times.

find:

What is the density of the mixture?​

-------------------------------------------------

let density (a) = 3.4 x 10^3 g/mL

density(b) = 1.5 x 10^1 g/mL

since there is no specific density provided for the mixture, we then add both to increase the density,

total density = density(a) + density(b)

total density = 3.4 x 10^3 g/mL + 1.5 x 10^1 g/mL

total density = 3.415 x 10^3 g/mL

therefore,

the total density of the mixture = 3.415 x 10^3 g/mL

5 0
3 years ago
Read 2 more answers
Provided is a diagram showing forces on a box.
Eduardwww [97]

Answer:

5 N left

Explanation:

trust me cccuuhh

4 0
3 years ago
When the following equation is balanced, what is the coefficient of oxygen?
Gwar [14]

Answer:

The answer is 3

C2H5OH + O2 CO2 +H2O (unbalanced)

C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)

4 0
3 years ago
The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compoun
GarryVolchara [31]

K_{sp} of the compound is found to be  5.04 ×10^{-10}.

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [A^{+} ]^{a} [B^{-} ]^{b}

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × 10^{-2} g/L

molar mass = 288 g/ mol

∴ s= 3.60 × 10^{-2} g/L ÷ 288 g/ mol = 1.25 ×10^{-4} mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

K_{sp} =[ M^{+3}] [ X^{-1}]^{3} = solubility product

∴ K_{sp} =[s]^{} [3s]^{3}

∴ K_{sp} = 3 s^{4}

∴ K_{sp} = 3 × (3.60 × 10^{-2} )^{4}

∴ K_{sp} = 503.8848 ×10^{-8}  = 5.04 ×10^{-10}

Learn more about solubility here .....

brainly.com/question/23946616

#SPJ1

7 0
2 years ago
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