The balanced equation for the neutralisation reaction is as follows
2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
stoichiometry of HNO₃ to Ba(OH)₂ is 2:1
number of Ba(OH)₂ mol present - 0.108 mol
1 mol of Ba(OH)₂ neutralises 2 mol of Ba(OH)₂
therefore 0.108 mol of Ba(OH)₂ neutralises - 2 x 0.108 mol = 0.216 mol of HNO₃
Molar C6H12O6 = 180.15 g/mol
180.15 g -------------- 6.02x10²³ molecules
?? g ------------------- 3.5x10²² molecules
( 3.5x10²²) x 180.15 / 6.02x10²³ =
=> 10.47 g
Answer:
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Answer:
V₂ =279.4 cm³
Explanation:
Given data:
Initial volume = 260 cm³
Initial temperature = 22.0°C
Final temperature = 44.0°C
Final volume = ?
Solution;
22.0°C (22+ 273 = 295k)
44.0°C(44+273 = 317k)
Formula:
According to Charles's law
V₁/T₁ = V₂/T₂
Now we will put the values in formula:
V₂ = V₁×T₂ / T₁
V₂ = 260 cm³ × 317k / 295k
V₂ = 82420 cm³. k / 295k
V₂ =279.4 cm³
When an atom gains two electrons, it becomes increasingly negative. In a neutral atom, there is the same number of protons and electrons to keep the atom charge free. By adding two electrons, you have thrown off the balance, making the atom negative
