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UkoKoshka [18]
3 years ago
7

A circle has radius of 18 cm. Find the area of the smaller of the two regions determined by a chord with length of 18√2 cm . Hin

t: (Look for right triangles using Pythagorean Theorem Converse)
Mathematics
2 answers:
boyakko [2]3 years ago
8 0
The area is 81*pi-162. Look at the triangle formed by the chord and the two radii connected to the endpoints of the chord. Since 18^2+18^2=(18*\sqrt2)^2, this is an isosceles right triangle by Pythagorean theorem. The area of the quarter circle containing the region we look for is pi*18^2/4=81*pi. The area of the right triangle is 18*18/2=162. The difference between these two areas, or 81*pi-162, is the area of the smaller region.
madreJ [45]3 years ago
3 0

Answer:

81pi - 162

Step-by-step explanation:

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