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beks73 [17]
3 years ago
15

A puck of mass 0.5100.510kg is attached to the end of a cord 0.8270.827m long. The puck moves in a horizontal circle without fri

ction. If the cord can withstand a maximum tension of 126126N, what is the highest frequency at which the puck can go around the circle without the cord breaking?
Physics
1 answer:
yanalaym [24]3 years ago
6 0

Answer: 2.75 1/sec

Explanation:

The only external force (neglecting gravity) acting on the puck, is the centripetal force, which. in this case, is represented by the tension in the string, so we can say:

T = mv² / r (1)

Our unknown, is the frequency at which the puck can go around the circle, which is the inverse of the period Tp.

By definition, a period is the time needed by the puck to complete one entire circle.

By definition also , angular velocity is the rate of change of the angle advanced, so we can express this way:

ω = ∆θ / ∆t  

The angle advanced during one period, is exactly (by angle definition) 2 π radians.

So, we can always write the angular velocity, ω, as follows:

ω = 2π / Tp = 2πf

Now, there is a relationship between linear and angular velocity, that can be found applying simply the definition of velocity and of an angle too, as follows:

v = ∆s / ∆t = r ∆θ/∆t = ω r

Replacing in (1), we have:

T = mω2 r2 / r = m ω2r (2)

We have just found that ω= 2πf, so, replacing in (2) :

T = m (2π)2 f2 r  

Solving for f:

f = 1/2π√(T/mr) = 1/2π 17.28 1/sec = 2.75 1/sec

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Addition of _____________ to pure water causes the least increase in conductivity. A) weak bases B) acetic acid C) ionic compoun
geniusboy [140]

Answer:

D

Explanation:

Water in itself is a bad conductor of electricity. Any compound that dissociates in water into ions and charged molecules, will increase conductivity of water. In this case ionic compounds weak basis and acids will put in free ions into the water. The ions can pass electricity because they are attracted to respective poles of electricity depending on their charges. In water, these ions are free moving unlike when they are immobilized in their lattice in solid form.

Organic compounds are mainly made of covalent bonds (around carbon) hence do not dissociate in water.

8 0
3 years ago
Read 2 more answers
The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee
lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is -27.3\hat{i}

y component of vector is 43.6\hat{j}

so position vector is

r=-27.3\hat{i}+43.6\hat{j}

Magnitude of vector is

|r|=\sqrt{27.3^2+43.6^2}

|r|=\sqrt{2646.25}

|r|=51.44 units

Direction

tan\theta =\frac{43.6}{-27.3}=-1.597

vector is in 2nd quadrant thus

180-\theta =57.94

\theta =122.06^{\circ}

4 0
3 years ago
A
True [87]

Answer:

\Delta T=3.615^{\circ}C is the drop in the water temperature.

Explanation:

Given:

  • mass of ice, m_i=14.7\ g=0.0147\ kg
  • mass of water, m_w=324\ g=0.324\ kg

Assuming the initial temperature of the ice to be 0° C.

<u>Apply the conservation of energy:</u>

  • Heat absorbed by the ice for melting is equal to the heat lost from water to melt ice.

<u>Now from the heat equation:</u>

Q_i=Q_w

m_i.L=m_w.c_w.\Delta T ......................(1)

where:

L= latent heat of fusion of ice =333.55\ J.g^{-1}

c_w= specific heat of water =4.186\ J.g^{-1}.^{\circ}C^{-1}

\Delta T= change in temperature

Putting values in eq. (1):

14.7 \times 333.55=324\times 4.186\times \Delta T

\Delta T=3.615^{\circ}C is the drop in the water temperature.

8 0
3 years ago
A golf ball reaches a height of 150 m before it stops rising and starts to fall to the ground. What is the golf balls speed (rou
artcher [175]

Answer:

v = 54 m/s

Explanation:

Given,

The maximum height of the flight of golf ball, h = 150 m

The velocity at height h, u = 0

The velocity of the golf ball right before it hits the ground, v = ?

Using the III equations of motion

                               <em>  v² = u² + 2gh</em>

Substituting the given values in the above equation,

                                 v² = 0 + 2 x 9.8 x 150 m

                                     = 2940

                                  v = 54 m/s

Hence, the speed of the golf ball right before it hits the ground, v = 54 m/s

4 0
3 years ago
A volleyball is spiked so that its incoming velocity of +2.63 m/s is changed to an outgoing velocity of -20.2 m/s. The mass of t
earnstyle [38]

Answer:

The impuise is 7.9905 kg*m/s

Explanation:

Step one:

given data

v1= +2.63m/s

v2=-20.2m/s

mass m= 0.350kg

Step two:

From the expression for impulse

Ft= mΔv

substituting our data into the expression we have

Ft= 0.35*(-20.2-2.63)

Ft= 0.35*22.83

Ft=7.9905 kg*m/s

8 0
2 years ago
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