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Nana76 [90]
3 years ago
15

One molecule of a compound weighs 2.03x10-22 g. what is the molar mass of that compound?

Chemistry
2 answers:
Sloan [31]3 years ago
7 0

The molar mass of the given compound is \boxed{122.2{\text{ g/mol}}}.

Further Explanation:

Molar mass:

The molar mass is the summation of masses of all atoms or molecule present in the 1 mole of compound. In other words, molar mass of a compound is the ratio of mass of compound in grams to the number of moles present of that compound. The S.I unit of molar mass is gram per mol or g/mol.

Mass of one molecule of a given compound is 2.03\times{10^{-22}}{\text{g}}.

According to Avogadro's number, the number of atoms or molecules present in the 1 mole of a substance is {\mathbf{6}}{\mathbf{.022\times1}}{{\mathbf{0}}^{{\mathbf{23}}}}.

Therefore, to calculate the mass of 1 mole of atoms, we have to multiply the mass of one molecule with the number of molecules present in 1 mole of given compound that is 6.022\times{10^{23}}.

The calculation for molar mass gives as follows:

\begin{gathered}  {\text{Molar mass}} = \left( {{\text{mass of 1 molecule}}\left( {\text{g}} \right)} \right)\left({{\text{number of molecules in 1 mole substance}}}\right)\\=\left({2.03\times{{10}^{-22}}{\text{g}}}\right)\left({6.022\times{{10}^{23}}{\text{ mo}}{{\text{l}}^{-1}}}\right)\\=\left({2.03\times 6.022}\right)\times{\text{1}}{{\text{0}}^{-22+23}}{\text{ g/mol}}\\=122.2{\text{ g/mol}}\\\end{gathered}

The value mass of 1 mole of given molecule is 122.2 g/mol.

Learn more:

1. Determined the mass of ammonia product formed in the reaction: brainly.com/question/6078553

2. Determine how many moles of water produce: brainly.com/question/1405182

Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Mole concept

Keywords: Potassium, molar mass, moles, atomic mass, number of moles, number of atoms, given mass, ratio, substance, g/mol grams, 78.20 grams, 2 moles, 39.098 g/mol, number of moles of potassium.

stealth61 [152]3 years ago
6 0
<span>The molar mass of the compound is 122 g. </span>
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Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

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                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

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For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

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                                  0.3673 g ---------------------   x

                                   x = (0.3673 x 1)/ 16

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Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

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