Here are the answers in order:
1. During a physical change the substance changes physically.
2. The law of conservation of mass is a law stating the conservation of mass cannot be higher than 46mg or lower than 32mg.
3. A hypothesis is a guess that you make before completing a science experiment, it can be considered a law because it is important to know why you are making the guess.
4. During a chemical change the mass is changing colors. This is a representation of a chemical change.
5. Oil is a non-renewable resource, so it cannot demonstrate the conservation of mass.
6. When the color of the substance has changed or when it explodes.
7. Reactants are the objects that react when in a chemical change.
8. If you follow the rule of not going higher than 46mg and not lower than 32mg then it will automatically follow this law.
Chemical Reactions Part One Video:
1. mass
2. erupt-ant
3. reactant
4. object
5. mixtures
6. molecules
7. color changed
Questions again:
1. A chemical reaction
2. A physical change
3. Because if it is no higher than 46mg and no lower than 32mg then it will follow on it's own.
The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1). In this model it is an essential feature that the photon energy (or frequency) of the electromagnetic radiation emitted (shown) when an electron jumps from one orbital to another, be proportional to the mathematical square of atomic charge (Z2). Experimental measurement by Henry Moseley of this radiation for many elements (from Z = 13 to 92) showed the results as predicted by Bohr. Both the concept of atomic number and the Bohr model were thereby given scientific credence. The atomic number is the number of _z_ an atom.
Answer:
<h2>The electrons in beryllium and magnesium are too strongly bound to get excited by flame. Hence, these elements do not impart any color.</h2>
Answer:
The molecular weight is ![Z = 111.2 \ g/mol](https://tex.z-dn.net/?f=Z%20%3D%20%20111.2%20%5C%20g%2Fmol)
Explanation:
From the question we are told that
The mass of the sample is ![m = 0.98 \ g](https://tex.z-dn.net/?f=m%20%3D%20%200.98%20%5C%20%20g)
The temperature is ![T = 348 K](https://tex.z-dn.net/?f=T%20%20%3D%20%20348%20K)
The volume which the gas occupied is ![V = 265 \ ml = 265 *10^{-3} L](https://tex.z-dn.net/?f=V%20%20%3D%20%20265%20%5C%20ml%20%20%3D%20265%20%2A10%5E%7B-3%7D%20L)
The pressure is ![P = 0.95 \ atm](https://tex.z-dn.net/?f=P%20%20%3D%20%200.95%20%5C%20%20atm)
Generally from the ideal gas equation we have that
![PV = n RT](https://tex.z-dn.net/?f=PV%20%20%3D%20%20n%20RT)
Here n is the number of moles of the gas while the R is the gas constant with value ![R = 0.0821 \ atm \cdot L \cdot mol^{-1} \cdot K^{-1}](https://tex.z-dn.net/?f=R%20%20%3D%20%200.0821%20%5C%20atm%20%5Ccdot%20L%20%20%5Ccdot%20mol%5E%7B-1%7D%20%5Ccdot%20K%5E%7B-1%7D)
![n = \frac{PV}{ RT}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7BPV%7D%7B%20RT%7D)
=> ![n = \frac{ 0.95 * 265 *10^{-3} }{ 0.0821 * 348}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B%200.95%20%2A%20265%20%2A10%5E%7B-3%7D%20%7D%7B%20%20%200.0821%20%2A%20348%7D)
=> ![n = 0.00881 \ mol](https://tex.z-dn.net/?f=n%20%3D%200.00881%20%5C%20%20mol)
Generally the molecular weight is mathematically represented as
![Z = \frac{m}{n}](https://tex.z-dn.net/?f=Z%20%3D%20%20%5Cfrac%7Bm%7D%7Bn%7D)
=> ![Z = \frac{0.98 }{0.00881}](https://tex.z-dn.net/?f=Z%20%3D%20%20%5Cfrac%7B0.98%20%7D%7B0.00881%7D)
=> ![Z = 111.2 \ g/mol](https://tex.z-dn.net/?f=Z%20%3D%20%20111.2%20%5C%20g%2Fmol)