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dedylja [7]
3 years ago
15

Infrared in __________controls

Chemistry
1 answer:
svetlana [45]3 years ago
8 0

Answer:

remote

Explanation:

i hope it helps

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What is the new temperature when 10 L at 5 K is compressed to 4.00 L
lina2011 [118]

Answer: C

Explanation:

For this problem, we would use Charles's Law. We fill in what we are given and solve.

Charles's Law: \frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

\frac{10 L}{5K} =\frac{4.00L}{T_{2} }

10T_{2}= 20

T_{2}=2K

4 0
3 years ago
What are the reactants in a cheese sandwich
Sedbober [7]

Answer:

cheese and bread

Explanation:

2 bread 1 cheese = cheese sandwich

3 0
3 years ago
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What volume is occupied by 16.4 g of mercury? The density of mercury is 13.6 g/mL
NeTakaya

Answer:

Brhrhrhrhhrhrhry hehhehdhdhhehehebebebbendjkdjdjfjcjbsksoejejjdnd

Explanation:

Dmdmsnsjsbbs नमस्कार ndjdjdjdjdjdjdjdhdjdjd ndndjdhdjdjdj ndjdjdjdjdjdjdjdhdjdjd ndndjd

3 0
3 years ago
7.no . <br> with steps please anyone <br> no spam
gulaghasi [49]
  • Given mass=1.3g
  • Atomic mass=65u

Molar mass=65g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto No\:of\;Moles=\dfrac{1.3}{65}=0.02mol

6 0
3 years ago
In a single replacement reaction between 2.57 moles Aluminum and 3.59 moles of Hydrochloric acid, how many moles of Hydrogen can
Alenkasestr [34]

Answer:

1.795 mole of H2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2Al + 6HCl —> 2AlCl3 + 3H2

Step 2:

Determination of the limiting reactant.

From the balanced equation above,

2 moles of Al reacted with 6 moles

Therefore, 2.57 moles of Al will react with = (2.57 x 6)/2 = 7.71 moles of HCl.

From the calculation made above, it will require a higher amount of HCl than what was given to react completely with 2.57 moles of Al. Therefore, HCl is the limiting reactant and Al is the excess reactant.

Step 3:

Determination of the number of mole H2 produced from the reaction.

Here, we shall be using the limiting reactant because it will produce the maximum yield of the reaction since all of it were consumed by the reaction.

The limiting reactant is HCl and the amount of H2 produce can be obtained as follow:

From the balanced equation above,

6 moles of HCl reacted to produce 3 moles of H2.

Therefore, 3.59 moles of HCl will produce = (3.59 x 3)/6 = 1.795 mole of H2.

From the calculations made above, 1.795 mole of H2 is produced from the reaction.

5 0
3 years ago
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