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Luda [366]
3 years ago
7

What is a limitation of using a chemical formula, such as CGH1206, to represent a compound?

Chemistry
1 answer:
Tpy6a [65]3 years ago
4 0

Answer:

The chemical formula does not show how the atoms are connected to one another.

Explanation:

With a chemical formula, you can see the types of elements that make up the compound, the number of atoms of each element in a molecule, and the chemical symbols of the elements in the compound.

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Answer choices:<br> A. Glass<br> B. Plastic <br> C. aluminum <br> D. Foam
Alona [7]

Answer:

I'm taking a guess here. Aluminum.

Explanation:

The best conductor of heat would be the material that melted the ice fast. A.K.A. the one with the least amount of minutes. Since aluminum has the least, it is the best conductor of heat

4 0
3 years ago
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D=___g/mL<br> v=100mL<br> m=1.5kg=___g
Bess [88]

The volume is 100mL.

The mass is 1.5kg which is equal to 1500g.

Thus, the density is 1500g / 100mL which is 15g/mL.

8 0
3 years ago
Carbon is black, crystalline and hard. Oxygen alone is a gas. How does the substance that is formed when these two elements comb
Margarita [4]
Carbon oxides (monoxide, dioxide) are gases :)
5 0
3 years ago
Both of the silicon-chlorine single bonds in sicl4 are polar. in which direction should the polarity arrows point?
o-na [289]

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6 0
3 years ago
At a festival, spherical balloons with a radius of 280. Cm are to be inflated with hot air and released. The air at the festival
evablogger [386]

Answer:

8608.18 balloons

Explanation:

Hello! Let's solve this!

Data needed:

Enthalpy of propane formation: 103.85kJ / mol

Specific heat capacity of air: 1.009J · g ° C

Density of air at 100 ° C: 0.946kg / m3

Density of propane at 100 ° C: 1.440kg / m3

First we will calculate the propane heat (C3H8)

3000g * (1mol / 44g) * (103.85kJ / mol) * (1000J / 1kJ) = 7.08068 * 10 ^ 6 J

Then we can calculate the mass of the air with the heat formula

Q = mc delta T

m = Q / c delta T = (7.08068 * 10 ^ 6 J) / (1.009J / kg ° C * (100-25) ° C) =

m = 93566.96kg

We now calculate the volume of a balloon.

V = 4/3 * pi * r ^ 3 = 4/3 * 3.14 * 1.4m ^ 3 = 11.49m ^ 3

Now we calculate the mass of the balloon

mg = 0.946kg / m3 * 11.49m ^ 3 = 10.87kg

The amount of balloons is

93566.96kg / 10.87kg = 8608.18 balloons

5 0
3 years ago
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