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3 years ago

C3H8 + 5O2 → 3CO2 + 4H2O

Chemistry

1 answer:

trasher [3.6K]3 years ago

7 0

Answer:

16.5moles of CO2

Explanation:

Molar mass of O2 is 32g/Mol

No of mole = 880/32 = 27.5 moles

27.5 Mol of O2 gives X mole of CO2

5 mole of O2 gives 3 moles of CO2

No of mole of CO2 = (27.5×3)/ 5 = 16.5moles

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An atom of calcium contains 20 protons how many electrons does it have

harina [27]

20.

Atomic number is equivalent to its protons and electrons. :)

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4 years ago

Where more of hydrogen are contained in 90 g of water or in 80 g of methane

Lynna [10]

Methane.

Water - H2O
Methane - CH4

Methane has 2 more hydrogens than water.

7 0

3 years ago

An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If

padilas [110]

Answer:- 1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

$\frac{V_1}{V_2}=\frac{n_1}{n_2}$

from given data, $V_1$ = 5.17 L, $n_1$ = 1.05 moles

$V_2$ = 8.00 L, $n_2$ = ?

Let's plug in the values in the formula:

$\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}$

On cross multiply:

$n_2=\frac{8.00L(1.05moles)}{5.17L}$

$n_2$ = 1.62 moles

So, now the toy contains 1.62 moles of the air.

5 0

3 years ago

80. Calculate AHıxn for the reaction: CaO(s) + CO2(g) → CaCO3().

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6 0

3 years ago

Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope

morpeh [17]

Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b:

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c:

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

3 0

3 years ago