Question

what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equation

Answer 1

Answer:

$Cu~+~PtCl_2->Pt~+~CuCl_2$

Explanation:

In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case $Pt^+^2$) and the anion is the atom at the right of the name (in this case $Cl^-$). With this in mind, the formula would be $PtCl_2$.

Now, if we used metallic copper we have to put in the reaction only the copper atom symbol $Cu$. So, we have as reagents:

$Cu~+~PtCl_2->$

The question now is: What would be the products? To answer this, we have to remember "single displacement reactions". With a general reaction:

$A~+~BC->AB~+~C$

With this in mind, the reaction would be:

$Cu~+~PtCl_2->Pt~+~CuCl_2$

I hope it helps!