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Sphinxa [80]
3 years ago
14

Choose a depiction of a gas sample containing equal molar amounts of xenon and argon as described by kinetic molecular theory. R

ed dots are used to represent xenon atoms and blue dots to represent argon atoms. Each atom is drawn with a "tail" that represents its velocity relative to the others in the mixture.

Chemistry
2 answers:
Setler79 [48]3 years ago
7 0

Answer:

On the attached picture.

Explanation:

Hello,

At first, it is important to remember that kinetic molecular theory help us understand how the molecules of a gas behave in terms of motion. In such a way, the relative velocity of a gas molecule has the following relationship with the gas' molar mass:

V∝\frac{1}{\sqrt{M} }

That is, an inversely proportional relationship which allows us to infer that the bigger the molecule the slower it. In this manner, as argon is smaller than xenon, it will move faster.

Now, as the gases are in equal molar amounts and considering that argon moves faster, on the attached picture you will find the suitable depiction of the gas sample, since red dots (argon) have a larger tail than the blue dots (xenon).

Best regards.

rusak2 [61]3 years ago
3 0

Answer:

<u>Kinetic Molecular theory(KMT):</u>Each molecules or atom of any gas is in a constant motion, and will have an elastic form of collision with other atoms present along with it inside any enclosed area or container.

And, the total kinetic energy of the molecules will be equal to the total or absolute temperature possessed by the number of atoms which are in motion inside the enclosed container.

Explanation:

<u>Xenon and Argon's molecules inside a container:</u>

When we study the properties of argon,Ar and xenon,Xe the denser molecule is the later one.As, the density of xenon,Xe is around 5.761 kg/m³, while the argon's density is about 1.7838 kg/m³. So, obviously the moment of argon's molecules will be more then that of xenon's. And the "tail" drawn with the molecules will be highlighted with high value of velocity inside the diagram.

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Hope this method helps! (This is my answer btw, I think you may have accidentally posted twice?)
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