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4 years ago

Which classification scheme is based on the brightness of a star as it appears to you in the night sky?

1 answer:

3 0

The apparent magnitude scale is a classification scheme which is based on the brightness of stars. The range of brightness values is from 1 to 6.
The stars which are the most brightest are ranked as number 1 and also called first magnitude stars, stars which are little dimmer than number 1 are ranked as number 2 and also called second magnitude stars. Similarly the most faintest stars are ranked number 6 and also called as the sixth magnitude stars.

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A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball

lora16 [44]

Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

Initial speed of the ball, u = 50.4 m/s

Final speed of the ball, v = -37 m/s (As it returns)

(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

$J=m(v-u)$

$J=0.06\times (-37-(50.4))$

J = -5.24 kg-m/s

(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

$W=\dfrac{1}{2}m(v^2-u^2)$

$W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)$

W = -35.1348 Joules

Hence, this is the required solution.

6 0

4 years ago

How much time does it take for a car to accelerate from 3.44 m/s to 20.9 m/s if the average acceleration is 6.00 m/s^3

miv72 [106K]

Do you go to GA Connexus Academy??

4 0

4 years ago

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What is the power in a circuit with a voltage of 120 V and a resistance of 50

k0ka [10]

Answer:

288W.

Explanation:

P = IV = V^2 / R = (120)^2 / 50 = 288W.

8 0

3 years ago

A wire is 1.1 m long and 0.91 mm in cross-sectional area. It carries a current of 4.4 A when a 1.8 V potential difference is app

Vlad [161]

Answer:

The conductivity of the material from which the conductor is made is 2.95 x10⁶ [S. m⁻¹] .

Explanation:

L= 1.1m

S= 0.91 mm²= 9.1 x10⁻⁷ m²

I= 4.4 A

V= 1.8V

$\frac{V}{I} =R\\\\\frac{1.8V}{4.4A} =R= 9/22 ohms$

R=9/22Ω

$R=\frac{L}{σ . S} \\\\Conductivity=sigma=\frac{L}{R.S} \\\\Conductivity= \frac{1.1m}{9/22 ohms . 9.1 E10 (-7) square meters}$

Conductivity=2.95 x10⁶ [S. m⁻¹]

3 0

3 years ago

In your own words, describe the purpose of using a chemical equation.

Scilla [17]

Chemical equations show how chemicals interact when a reaction occurs. They use symbols and formulas to show the chemical reaction so that chemical names do not need to be written out. They also help keep track of all elements and the number of atoms of each element on each side of the equation.

7 0

4 years ago

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