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3 years ago

If ball 4 has a mass of 2 kg and it is 5m high, what will be its gravitational potential energy? (g=10 N/kg) *

Physics

2 answers:

Sidana [21]3 years ago

5 0

Answer:

$\boxed {\boxed {\sf 100 \ Joules}}$

Explanation:

Gravitational potential energy can be found using the following formula.

$E_p=m*g*h$

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass of the ball is 2 kilograms, its height is 5 meters, and the acceleration due to gravity is 10 Newtons per kilogram.

$m= 2 \ kg \\h= 5 \ m \\g= 10 \ N/kg$

Substitute the values into the formula.

$E_p=(2 \ kg)(10 \ N/kg)(5 \ m)$

Multiply the first 2 numbers. The kilograms (kg) will cancel out when multiplying.

$E_p=(20 \ N)(5 \ m)$

Multiply again.

$E_p=100 \ N*m$

1 Newton meter is equal to 1 Joule
Therefore, 100 N*m= 100 J

$E_p= 100 \ J$

The gravitational potential energy of the ball is 100 Joules.

Nastasia [14]3 years ago

3 0

Explanation:

Gravitational potential energy

= mgh

= (2kg)(10N/kg)(5m)

= 100J.

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A 94 g particle undergoes SHM with an amplitude of 8.3 mm, a maximum acceleration of magnitude 7.8 x 103 m/s2, and an unknown ph

Lelechka [254]

Answer:

a) T = 6.49*10^-3 s

b) v = 8 m/s

c) E = 3 J

d) F = 733 N

e) F = 366.5 J

Explanation:

Given

Mass of particle, m = 94 g = 0.094 kg

Amplitude of the particle, A = 8.3 mm = 8.3*10^-3 m

Maximum acceleration of particle, a = 7.8*10^3 m/s²

the equation describing Simple Harmonic Motion is given as

x = A cos (wt +φ)

To fond the acceleration of this relationship, we would have to integrate. Twice, the first would be a Velocity, and the second acceleration that we need.

Velocity = dx/dt = -Aw sin(wt + φ)

Acceleration = d²x/dt = -Aw² cos(wt + φ)

From the question, we were given, magnitude of acceleration to be 7.8*10^3 m/s²

Aw² = 7.8*10^3

w² = 7.8*10^3 / A

w² = 7.8*10^3 / 8.3*10^-3

w² = 939759

w = √939759

w = 969

Recall, T = 2π/w, so that

T = (2 * 3.142) / 969

T = 6.49*10^-3 s

Maximum speed = Aw

Maximum speed = 8.3*10^-3 * 969

Maximum speed = 8.0 m/s

Total mechanical energy oscillator =

mgx + 1/2mx² =

1/2mv(max)² =

1/2 * 0.094 * 8² =

3 J

Maximum displacement

x = A cos(wt + φ)

For x to be maximum here, then cos(wt + φ) Must be equal to 1

Acceleration = d²x/dt² = -Aw²

And force = mass * acceleration

Force = 0.094 * 7.8*10^3

Force = 733 N

x = A cos(wt + φ), where cos(wt + φ) = 1/2

d²x/dt² = -Aw² * 1/2

d²x/dt² = 733 * 0.5

= 366.5 N

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https://doubtnut.app.link/FnsNC80Dccb

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3 years ago

It takes 5.0 seconds for a wave with a wavelength of 2.5 m to travel past your location. What’s the period of the wave. What is

Anna35 [415]

(a) Period of the wave
The period of a wave is the time needed for a complete cycle of the wave to pass through a certain point.
So, if an entire cycle of the wave passes through the given location in 5.0 seconds, this means that the period is equal to 5.0 s: T=5.0 s.

(b) Frequency of the wave
The frequency of a wave is defined as
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since in our problem the period is $T=5.0 s$ , the frequency is
$f= \frac{1}{5.0 s}=0.2 Hz$

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The speed of a wave is given by the following relationship between frequency f and wavelength $\lambda$ :
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3 years ago

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andreev551 [17]

Answer: Teeth is an example of a wedge.

Explanation :

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