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victus00 [196]
3 years ago
11

If ball 4 has a mass of 2 kg and it is 5m high, what will be its gravitational potential energy? (g=10 N/kg) *

Physics
2 answers:
Sidana [21]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 100 \ Joules}}

Explanation:

Gravitational potential energy can be found using the following formula.

E_p=m*g*h

where <em>m</em> is the mass, <em>g</em> is the gravitational acceleration, and <em>h </em>is the height.

The mass of the ball is 2 kilograms, its height is 5 meters, and the acceleration due to gravity is 10 Newtons per kilogram.

m= 2 \ kg \\h= 5 \ m \\g= 10 \ N/kg

Substitute the values into the formula.

E_p=(2 \ kg)(10 \ N/kg)(5 \ m)

Multiply the first 2 numbers. The kilograms (kg) will cancel out when multiplying.

E_p=(20 \ N)(5 \ m)

Multiply again.

E_p=100 \ N*m

  • 1 Newton meter is equal to 1 Joule
  • Therefore, 100 N*m= 100 J

E_p= 100 \ J

The gravitational potential energy of the ball is <u>100 Joules.</u>

Nastasia [14]3 years ago
3 0

Explanation:

Gravitational potential energy

= mgh

= (2kg)(10N/kg)(5m)

= 100J.

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The launch velocity of the projectile is 13.28 m/s.

What is projectile motion?

The motion of an object thrown in the air under the force of gravity is known as projectile motion.

Since the object is launched horizontally, its initial velocity along the vertical direction is zero. From the second kinematic equation,

s=u*t+(1/2)at^2.

where s is the displacement, t is the time, u is the initial velocity and a is the acceleration. Since the height is decreasing, so it will be taken negative.

For the vertical motion, s=-19.3 m, a=-9.8 m/s^2 and u=0. Put the values in the above equation and solve it.

-19.3 = (0)*t+(1/2)*(-9.8)*t^2

19.3 = (1/2)*(9.8)*t^2

t=1.98 s

Since the velocity along the horizontal direction is constant, the displacement along the horizontal direction is given by the formula,

X=vt

where X is the horizontal displacement, v is the initial horizontal velocity and t is the time.

For the horizontal motion, X=26.3 m and t=1.98 s. Put the values in this equation and solve it.

26.3=v*(1.98)

v=13.28 m/s

The launch velocity is equal to the initial horizontal velocity, so it is equal to 13.28 m/s.

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asambeis [7]

Answer:

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Explanation:

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The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.

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The time of motion of the particle is calculated by applying Newton's second law of motion.

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