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4 years ago

Plz help, idk this!!!!!!!!!!!!

Mathematics

1 answer:

Lena [83]4 years ago

5 0

Answer: L=13

Step-by-step explanation: Multiply your eight and five...

5•8=40

Then...Divide forty by two-hundred-fifty...

250/40=13.

You ALWAYS want to check your answer by multiplying to see if you are absolutely correct.

So...5•8•13=250.

Your answer is...Length = 13.

I hope this helps you!

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Suppose that 10% of adults belong to health clubs, and 40% of these health club members go to the club at least twice a week. Wh

kozerog [31]

Answer:

4% of all adults go to a health club at least twice a week

Step-by-step explanation:

the proportion of adults who belong to health clubs is 10% that is 0.10

the proportion of these adults (health club members) go to the club at least twice a week is 40%, that is 0.40.

Thus, the proportion of all adults go to a health club at least twice a week is

0.10 × 0.40 = 0.04, that is 4%

3 0

4 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago

A player in a game must roll a fair six-sided number cube and then flip a coin. What is the probability of a player rolling 4 an

expeople1 [14]

Answer:

Step-by-step explanation:

P(4) = 1/6

P(h) = 1/2

P(both) = 1/2 * 1/6 = 1/12

7 0

3 years ago

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible o

Agata [3.3K]

Answer:

$\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}$

Step-by-step explanation:

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible outcomes: BBBB, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and GGGG.

Let X represent the number of children that are girls. Then

1. When X=0, there is one possible outcome BBBB. So

$Pr(X=0)=\dfrac{1}{16}$