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Tpy6a [65]
3 years ago
11

What percentage of the ATP generated from glucose results from oxidative phosphorylation via electron transport chain?

Chemistry
1 answer:
cestrela7 [59]3 years ago
8 0
90% is correct......
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No matter how much water a human drinks, the kidneys are always regulating various aspects of the blood, including _____________
Snowcat [4.5K]

The answers are I, II and IV

No matter how much water a human drinks, the kidneys are always regulating various aspects of the blood, including the pH of the blood, the plasma concentration of iron ions and the plasma concentration of potassium ions.

 






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The cell of your body need energy to carry out life function. Which of the following body responses is a sign that your cells ne
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Which type of acetylcholine receptor is present on postganglionic neurons
Sonja [21]

Answer:

Mescarinic and Nicotinic

Explanation:

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4 0
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3 0
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Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
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