What percentage of the ATP generated from glucose results from oxidative phosphorylation via electron transport chain?

3. A 3.455-g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of

erik [133]

Answer:

$Ba\ percentage\ in\ Mass=4.8\%$

Explanation:

From the question we are told that:

Mass of mixture $m=3.455g$

Mass of Barium $m_b=0.2815g$

Equation of Reaction is given as

$Ba2+ + H2SO4 => BaSO4 + 2 H+$

Generally the equation for Moles of Barium is mathematically given by

Since

$Moles of Ba^{2+} = Moles of BaSO_4$

Therefore

$Moles of Ba^{2+} = \frac{mass}{molar mass of BaSO4}$

$Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol$

Generally the equation for Mass of Barium is mathematically given by

$Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}$

$Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g$

Therefore

$Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%$

$Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%$

$Ba\ percentage\ in\ Mass=4.8\%$

8 0

3 years ago

A cube of salt is crushed before being stirred into water.

andrew-mc [135]

Physical change

Giddy Up!!!!!

7 0

4 years ago

Read 2 more answers

Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U

Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$ ..........(1)

where,

$R_1$ = rate of effusion of nitrogen gas = $79mL/s$

$R_2$ = rate of effusion of sulfur dioxide gas = ?

$M_1$ = molar mass of nitrogen gas = 28 g/mole

$M_2$ = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

$(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}$

$R_2=52mL/s$

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0

3 years ago

Which factor does not influence stream velocity

baherus [9]

The factor that does not influence stream velocity is DISCHARGE.
Stream velocity refers to the speed with which the water in a stream is flowing. The factors which affect stream velocity include channel size, channel shape, turbulent flow and gradient.

3 0

4 years ago

Read 2 more answers

A solution of an unknown nonvolatile nonelectrolyte was prepared by dissolving 0.250 g of the substance in 40.0 g of ccl4. the b

Finger [1]

Answer : The molar mass of the solute will be 87.90 g/mol.

Explanation : We know the formula for elevation in boiling point, which is

Δt = i $K_{b}$ m

given that, Δt = 0.357, $K_{b}$ = 5.02 and mass of $CCl _{4}$ = 40,

on substituting the value we get,
0.357 = (1) X (5.02) X (x/ 0.044), on solving we get x = 2.844 X $10^{-3}$ .
Now, 0.250/ 2.844 X $10^{-3}$ = 87.90 g/mol. which is the weight of unknown component.

3 0

3 years ago