All options are as follow,
<span>A. PbS + O2→ PbO + SO</span>₂<span>
B. PbS + 2O</span>₂<span>→ PbO + 2SO</span>₂<span>
C. 2PbS + 2O</span>₂<span>→ 2PbO + 2SO</span>₂<span>
D. 2PbS + 3O</span>₂<span>→ 2PbO + 2SO</span>₂<span>
E. 3PbS + 3O2→ 2PbO + 2SO2
Option A is not balanced because the number of oxygen atoms are greater at right hand side.
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Option B is not balanced because the number of oxygen are less at right hand side and number of sulfur atoms are greater at right hand side.
Option C is not balanced because the number of oxygen atoms are greater at right hand side.
Option D is Balanced, all elements are balanced at both sides.
Option E is not balanced because number of Lead and Sulfur atoms are greater at right hand side.
Result:
Equation in Option D is balanced and correct answer.
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The Diesel cycle<span> is a combustion process of a reciprocating </span>internal combustion in the cylinders of the engine<span>. In it, </span>fuel<span> is ignited by heat generated during the compression of air in the combustion chamber, into which fuel is then injected and the exhaust from the combustion is pushed out the exhaust pipe or brought out by a turbo </span>
Answer : The volume in mL of the sodium carbonate stock solution is 364 mL.
Explanation :
According to dilution law:
where,
= molarity of aqueous sodium carbonate
= molarity of aqueous sodium carbonate stock solution
= volume of aqueous sodium carbonate
= volume of aqueous sodium carbonate stock solution
Given:
= 1.00 M
= 1.58 M
= 575 mL
= ?
Now put all the given values in the above formula, we get:
Therefore, the volume in mL of the sodium carbonate stock solution is 364 mL.