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Simora [160]
3 years ago
6

Which of the following statements is NOT a part of John Dalton's atomic theory?

Chemistry
1 answer:
Goshia [24]3 years ago
7 0

The statement that is NOT a part of John Dalton's atomic theory Electrons move in specific orbits around the nucleus of an atom. The statements ‘All elements are composed of atoms that cannot be divided’, ‘All atoms of the same element are exactly alike and have the same mass’ and ‘Every compound is composed of atoms of different elements, combined in a specific ratio’ are not his theory.

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Which of the following elements is an example of a metalloid?
8_murik_8 [283]
Sodium is an earth-metal (group one), sliver and platinum are d-block metals.... Thus silicon is the metalloid and that is true because it looks like a metal being shiny blue-gray but it exhibit non-metal characteristics, except the fact that it can conduct electricity in a heated state.
8 0
3 years ago
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Compare the change in pH with the addition of acid and base to deionized water and to a buffer.
iogann1982 [59]

Answer:

case1.

The addition of acid and base leads to a change in pH of the water when adding to deionized water due to fact that acid and bases dissociated in dissolving in water. If the H+ ion increases in the water as acid addition hikes it, it will result in decreasing the pH value. The intensity of the acid also affects the dissociation of the ions.

case2

Buffers are normally formed by weak acid and its conjugate base, and adding acid to the buffer it absorbs the H+ ions so the pH will be lower and adding base or increase of OH- conjugate base resists the pH value to increase.

5 0
3 years ago
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

Best regards!

6 0
2 years ago
An object has a density of 10.00 g/mL. If the object has a volume of<br> 25.00 ml, what is the mass?
SVEN [57.7K]

Answer:

The answer is

<h2>250 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 25 mL

Density = 10 g/mL

The mass of the object is

mass = 25 × 10

We have the final answer as

<h3>250 g</h3>

Hope this helps you

6 0
3 years ago
A student had a sample of pure water, and added an unknown substance to it. The student noticed that the hydroxide ion concentra
steposvetlana [31]
The answer is A it's a basic because once you add another substance to a neutral it either becomes acidic or basic. this one becomes basic because the hydroxide ion concentrate increased.
6 0
3 years ago
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